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Critical-rank representatives of rank-zero classes
PDF p. 12: Proof of Theorem A, rank two representative; PDF p. 15: Proof of Theorem 6.7, first sentence; PDF p. 17: Proof of Theorem B, rank three representatives
Statement
Assume the Axiom of Choice and suitable universes. Let be a nonempty affine scheme of finite type over a field, of dimension or . Every class of pointwise rank zero in can be written for a vector bundle of constant rank . Moreover, any vector bundle of constant rank is isomorphic to for a vector bundle of rank .
A vector bundle is a finite locally free -module; its rank at a point is the number of copies of the structure sheaf in a local trivialization there. Constant rank means the same rank at every point. The dimension is the supremum of the lengths of strict chains of irreducible closed subsets. The spectrum is the nonconnective K-theory of perfect complexes in the supplied interface. The class of a vector bundle in is the class of the complex concentrated in degree zero. Pointwise rank on is transported through the affine K-zero isomorphism to the rank homomorphism on the vector-bundle Grothendieck group: a difference has rank at .
Facts & Assumptions
Given: The Axiom of Choice, suitable universes, and and as in the statement.
Goal: Represent every pointwise rank-zero class by a rank- bundle minus the trivial rank- bundle, and split any constant-rank bundle down to rank .
The Axiom of Choice is used through the assumed contracts of the affine perfect-K-zero bridge and finite-projective-complement suppliers in step 1.1, and of Serre splitting in steps 3.1 and 4.1. Padding in step 2.1 requires no additional choice. The Axiom of Choice
For an affine scheme, the supplied bridge identifies with the vector-bundle Grothendieck group and sends the spectral class of a bundle to its bundle class. This requires the Axiom of Choice and suitable universes. Affine perfect K zero and bundle K zero
For a locally noetherian affine scheme, under the Axiom of Choice, each element of is for some vector bundle and integer . Its rank at is . The construction uses a finite projective complement to turn the negative bundle into a trivial bundle. Finite projective complements
Under the Axiom of Choice, on a nonempty noetherian affine scheme of dimension , a constant-rank- vector bundle with is isomorphic to a rank- bundle plus trivial line summands. Serre splitting above the dimension
Proof
A finite-type algebra over a field is noetherian, so is noetherian and locally noetherian. By [F1] and [F2], write the given rank-zero class as with . Since its rank is zero at every point, [F2] gives for every ; thus has constant rank .
If , put . Then has rank , and the direct-sum relation in gives .
If , apply [F3] to to obtain with of rank . The direct-sum relation gives . Together with step 2.1, this proves the representative assertion in all cases.
For the additional assertion, if take ; the trivial rank-zero bundle is the zero bundle. If , [F3] directly supplies with of rank . This proves the stated splitting as well as the representative claim.
Depends on
Dependency tree · 3 levels
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Sources
- Jean Fasel and Maria Yakerson, Vector bundles on singular surfaces and threefolds · PDF pp. 12, 15 and 17, applications of Serre splitting