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Critical-rank representatives of rank-zero classes

PDF p. 12: Proof of Theorem A, rank two representative; PDF p. 15: Proof of Theorem 6.7, first sentence; PDF p. 17: Proof of Theorem B, rank three representatives

Statement

Assume the Axiom of Choice and suitable universes. Let X be a nonempty affine scheme of finite type over a field, of dimension d=2 or 3. Every class α of pointwise rank zero in K0(X)=π0K(X) can be written α=[E]−[OXd] for a vector bundle E of constant rank d. Moreover, any vector bundle V of constant rank r≥d is isomorphic to E′⊕OXr−d for a vector bundle E′ of rank d.

A vector bundle is a finite locally free OX-module; its rank at a point is the number of copies of the structure sheaf in a local trivialization there. Constant rank means the same rank at every point. The dimension is the supremum of the lengths of strict chains of irreducible closed subsets. The spectrum K(X) is the nonconnective K-theory of perfect complexes in the supplied interface. The class of a vector bundle in K0(X) is the class of the complex concentrated in degree zero. Pointwise rank on K0(X) is transported through the affine K-zero isomorphism to the rank homomorphism on the vector-bundle Grothendieck group: a difference [B]−[C] has rank rank⁡xB−rank⁡xC at x.

Facts & Assumptions

Given: The Axiom of Choice, suitable universes, and X and d as in the statement.

Goal: Represent every pointwise rank-zero class by a rank-d bundle minus the trivial rank-d bundle, and split any constant-rank bundle down to rank d.

[A1]

The Axiom of Choice is used through the assumed contracts of the affine perfect-K-zero bridge and finite-projective-complement suppliers in step 1.1, and of Serre splitting in steps 3.1 and 4.1. Padding in step 2.1 requires no additional choice. The Axiom of Choice

[F1]

For an affine scheme, the supplied bridge identifies K0(X) with the vector-bundle Grothendieck group K0(X) and sends the spectral class of a bundle to its bundle class. This requires the Axiom of Choice and suitable universes. Affine perfect K zero and bundle K zero

[F2]

For a locally noetherian affine scheme, under the Axiom of Choice, each element of K0(X) is [B]−[OXN] for some vector bundle B and integer N≥0. Its rank at x is rank⁡xB−N. The construction uses a finite projective complement to turn the negative bundle into a trivial bundle. Finite projective complements

[F3]

Under the Axiom of Choice, on a nonempty noetherian affine scheme of dimension d, a constant-rank-r vector bundle with r>d is isomorphic to a rank-d bundle plus r−d trivial line summands. Serre splitting above the dimension

Proof

technique · First use a finite projective complement to obtain a single bundle minus a trivial bundle, then pad or split off trivial summands
1.1A1F1F2given

A finite-type algebra over a field is noetherian, so X is noetherian and locally noetherian. By [F1] and [F2], write the given rank-zero class as α=[B]−[OXN] with N≥0. Since its rank is zero at every point, [F2] gives rank⁡xB=N for every x; thus B has constant rank N.

2.1F1step 1.1construct

If N≤d, put E=B⊕OXd−N. Then E has rank d, and the direct-sum relation in K0(X) gives [E]−[OXd]=[B]−[OXN]=α.

3.1A1F1F3step 1.1step 2.1

If N>d, apply [F3] to B to obtain B≅E⊕OXN−d with E of rank d. The direct-sum relation gives [B]−[OXN]=[E]−[OXd]. Together with step 2.1, this proves the representative assertion in all cases.

4.1A1F3givenstep 3.1∎

For the additional assertion, if r=d take E′=V; the trivial rank-zero bundle is the zero bundle. If r>d, [F3] directly supplies V≅E′⊕OXr−d with E′ of rank d. This proves the stated splitting as well as the representative claim.

Depends on

Used by · 3

Dependency tree · 3 levels

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Sources