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Rank-three representatives with two zero Chern classes

PDF p. 15: First sentence of Theorem 6.7 proof

Statement

Assume the Axiom of Choice and the site and universe size bounds required by the completed filtration and Chern comparisons. Let k be an algebraically closed field and let X be a normal affine k-scheme of finite type and dimension three. Every α∈Fmot3K0(X) can be written α=[P]−[OX3] for a rank-three vector bundle P with c1(P)=0, c2(P)=0, and det⁡P≅OX.

A vector bundle is a finite locally free OX-module, and rank three means that it is locally isomorphic to OX3. Its determinant is the line bundle ⋀3P. Normal means that every local ring is an integrally closed domain; finite type means that the affine coordinate ring is a finitely generated k-algebra. Dimension is the supremum of lengths of strict chains of irreducible closed subsets. Here K0(X)=π0K(X) for the specified nonconnective K-theory spectrum of perfect complexes, and [P] denotes the class of P concentrated in degree zero. The subgroup FmotiK0(X) is the image of the zeroth homotopy group of the ith motivic filtration stage in K0(X). The bundle Chern classes ci(P) lie in Hmot2i,i(X,Z) and are the classes defined by the supplied motivic projective-bundle relation. Choice asserts that every family of nonempty sets has a choice function; the size bounds fix the sites and ambient universes of the cited comparisons.

Facts & Assumptions

Given: k, X, α, Choice, and the site and universe bounds as stated.

Goal: Construct a rank-three representative and prove the two Chern-class vanishings and determinant triviality.

[F1]

The motivic image filtration is decreasing: Fmot3K0(X)⊆Fmot2K0(X). Motivic filtration and image groups

[F2]

Every class in the second image piece has pointwise rank zero and first perfect Chern class zero. If it is a difference of two bundle classes, the two bundles have isomorphic determinants. Rank and determinant on the second piece

[F3]

Under Choice as in The Axiom of Choice and suitable universes, every pointwise rank-zero perfect K-zero class on a nonempty affine finite-type field-scheme of dimension three has the form [P]−[OX3] with P of constant rank three. Critical-rank representatives of rank-zero classes

[F4]

On the second image piece, the actual second projection p2 is minus the actual perfect second Chern operation, and its kernel is the third image piece. No injectivity of the third stage into K-zero is required. Second projection is minus second Chern class

[F5]

For a bundle difference [V]−[W] in the second image piece, the actual perfect operation satisfies c2([V]−[W])=c2(V)−c2(W). Second Chern additivity on the second piece

[F6]

The total bundle Chern class is multiplicative on direct sums, and a line bundle has no Chern classes above degree one. Whitney identities and virtual Chern arithmetic

Proof

technique · Represent the rank-zero class at the critical rank, then apply the actual filtration projections and bundle comparison
1.1F1F2F3given

Since X has dimension three it is nonempty. By [F1], α lies in the second image piece, so [F2] gives pointwise rank zero. Applying [F3] yields a rank-three vector bundle P with α=[P]−[OX3].

2.1F2step 1.1

The bundle-difference assertion of [F2], applied to the expression in step 1.1, gives det⁡P≅det⁡(OX3). The standard basis trivializes the latter determinant, so det⁡P≅OX. The first perfect Chern class of α is zero by [F2]; its bundle-difference comparison in the same supplied contract, together with the first-class normalization for the trivial determinant, gives c1(P)=0. Equivalently, the determinant comparison identifies c1(P) with the image of the trivial line under the weight-one orientation.

2.2F2F4F5F6step 1.1

Since α belongs to the third image piece, [F4] gives p2(α)=0, hence c2(α)=0. By [F5] and step 1.1, c2(α)=c2(P)−c2(OX3). The latter trivial bundle is a direct sum of three trivial lines. Its total Chern class is 1: the first class of the trivial line is zero by the determinant normalization in [F2], its higher classes vanish by [F6], and [F6] multiplies the three total classes. Thus c2(OX3)=0, and consequently c2(P)=0.

3.1step 1.1step 2.1step 2.2∎

Steps 1.1 through 2.2 prove all the stated assertions.

Depends on

Used by · 1

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