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Torsion freeness after removing a smooth-locus integral curve

PDF p. 13: Proposition 6.1 and proof

Statement

Assume the Axiom of Choice and the size conventions of Motivic and filtered K theory with support. Let X be an affine finite-type threefold over an algebraically closed field k, and let T⊂X be a closed integral curve contained in the smooth locus Xsmooth. Then Hmot6,3(X∖T,Z) is torsion-free.

A threefold here is a finite-type k-scheme of dimension three; no reducedness, irreducibility, normality, or smoothness of X is assumed. An integral curve is a reduced irreducible scheme of dimension one. The smooth locus consists of the points at which X→Spec⁡k is smooth. A group is torsion-free if na=0 for a positive integer n implies a=0. The motivic cohomology group is the degree-six cohomology of the weight-three motivic complex, as defined in Motivic complexes and cohomology. The Axiom of Choice is used through the two supported-cohomology suppliers, including their size and comparison constructions.

Facts & Assumptions

Given: An affine finite-type threefold X over an algebraically closed field k, a closed integral curve T⊂Xsmooth, the Axiom of Choice, and the size conventions of Motivic and filtered K theory with support.

Goal: Prove that Hmot6,3(X∖T,Z) is torsion-free.

[F1]

Motivic and filtered K theory with support defines the weight-three support spectrum as the fiber of restriction from X to X∖T, with supported cohomology Hmot,Ta,3(X,Z)=π−aM3(X/(X∖T)). On the qcqs schemes in this statement, Motivic complexes and cohomology identifies the corresponding ordinary groups with cohomology of the evaluated motivic complexes. Homotopy exactness of a spectral fiber sequence supplies the long exact homotopy sequence of this actual fiber sequence.

[F2]

Torsion freeness of top threefold motivic cohomology says that Hmot6,3(X,Z) is torsion-free for an affine finite-type threefold over an algebraically closed field, without extra hypotheses on X.

[F3]

Under the given field, geometry, choice and size hypotheses, Divisibility of curve-supported top cohomology says that the image of the actual support-to-global map in degree six is divisible, and Supported degree-seven vanishing says that the supported group in degree seven is zero. A group is divisible when multiplication by every positive integer is surjective.

[F4]

Quotient by a divisible subgroup says that in a short exact sequence 0→D→G→A→0 of abelian groups, if D is divisible and G is torsion-free, then A is torsion-free. Short exact means that the first map is injective, the second is surjective, and the image of the first equals the kernel of the second.

Proof

technique · Apply the support long exact sequence and the divisible-quotient lemma
1.1F1given

Put V=X∖T. Since X is noetherian, its open subset V is quasi-compact; both are quasi-separated. The fiber sequence of [F1], followed by its long exact homotopy sequence with the given indexing, yields the exact segment Hmot,T6,3(X,Z)⟶Hmot6,3(X,Z)→ρHmot6,3(V,Z)⟶Hmot,T7,3(X,Z). The first map is support-to-global and ρ is restriction.

2.1F3step 1.1given

The hypotheses of both suppliers in [F3] hold for the given X, k and T, with the stated choice and size conventions. Thus the last group in step 1.1 is zero, and the image D of the first map is divisible. Exactness makes ρ surjective and identifies its kernel with D.

3.1F2F4step 2.1∎

Write G=Hmot6,3(X,Z) and A=Hmot6,3(V,Z). The inclusion of D into G and ρ form a short exact sequence 0→D→G→A→0. By [F2], G is torsion-free; by step 2.1, D is divisible. Applying [F4] proves that A is torsion-free, as required.

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