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2 results · all verified · 2 also independently AI-judged
Every result on this page is machine-checked by a proof checker and read in full and owner-audited; the judge is an additional, independent cross-model AI review of the proofs; all 2 also cleared it.

Projective Algebraic Sets Projective Morphisms and Cones — Examples

1 · Prerequisites

2 · Summary

These examples make the infrastructure concrete through explicit chart, closure, conic, cone, and coordinate-map computations. The companion develops homogeneous equations, affine charts, projective closure and saturation, regular functions, coordinate morphisms, and affine cones.

3 · Logical flowchart

4 · Definitions, theorems and proofs

None yet.

5 · Examples, counterexamples and false statements

ExampleConstruction: Literature-sourcedVerification: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-06Open item page →

projective line two affine charts

Example

For Pk1, U0=D+(X) has coordinate t=Y/X and U1=D+(Y) has coordinate s=X/Y. On U0U1, both coordinates are nonzero and s=1/t. Thus the two affine lines glue by inversion; t=0 is [1:0] and the point outside U0 is [0:1].

ExampleConstruction: Literature-sourcedVerification: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-06Open item page →

projective closure parabola

Example

For the parabola A=V(yx2)Ak2, use homogeneous coordinates [Z:X:Y]. Its homogenization is YZX2, so Aproj=V+(YZX2). The Z=1 chart is y=x2. At infinity Z=0, the equation gives X=0, leaving exactly [0:0:1].

CounterexampleConstruction: Literature-sourcedVerification: AI-adaptedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-06Open item page →

naive homogenization adds component

Statement refuted

Raw homogenization of arbitrary generators always gives the projective closure.

Counterexample

Given: I=(x1,xy)k[x,y], with projective coordinates [Z:X:Y].

1.1

The raw homogenized generators are XZ and XY, whose common projective zeros include [0:0:1]: both polynomials vanish there.

givenalgebra
2.1

Since xyy(x1)=y, one has I=(x1,y); hence V(I)={(1,0)} and its closure is V+(XZ,Y), which does not contain [0:0:1].

step 1.1algebra
3.1

Thus raw generators introduce a spurious point at infinity; saturation removes it and is necessary.

step 2.1
ExampleConstruction: Literature-sourcedVerification: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-06Open item page →

projective conic standard charts

Example

For Q=V+(XZY2)Pk2, the X=1 chart has equation z=y2, and the Z=1 chart has equation x=y2. The Y=1 chart has equation xz=1. These are the standard affine pieces, related on overlaps by ratio-coordinate changes.

ExampleConstruction: Literature-sourcedVerification: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-06Open item page →

affine cone over conic

Example

Assume chark2. The affine cone over V+(XZY2) is V(XZY2)Ak3. Its partial derivatives are Z,2Y,X, all zero at (0,0,0); the defining equation also vanishes there. This is the elementary hypersurface-derivative diagnostic at the vertex only, not an invocation of a general singular-locus theorem.

CounterexampleConstruction: AI-generatedVerification: AI-adaptedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-06Open item page →

inhomogeneous equation not projectively well defined

Statement refuted

An arbitrary polynomial equation has a representative-independent zero locus in projective space.

Counterexample

Given: A field k of characteristic not equal to 2, the inhomogeneous polynomial x0+1, and the projective point [1:0]Pk1.

1.1

The vectors (1,0) and (1,0) represent the same projective point, but x0+1 takes the nonzero value 2 at the first and the value 0 at the second.

givenalgebra
2.1

Thus the vanishing decision changes with the representative, refuting the assertion.

step 1.1
ExampleConstruction: Literature-sourcedVerification: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-06Open item page →

morphism projective line power map

Example

For d1, [X:Y][Xd:Yd] is defined because Xd,Yd have common degree and no common projective zero. On X0 it is t=Y/Xtd, and on Y0 it is s=X/Ysd. The formulas agree under s=1/t.

Sources