Alphabeta Math
CounterexampleConstruction: AI-adaptedVerification: AI-generatedprecheck passaudited 2026-08-31
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A Cauchy sequence in calligraphic Lp can converge to two distinct functions

Statement refuted

In the representative space Lp(μ), the p-distance always gives unique limits.

Facts & Assumptions

Given: A nonzero null-supported function from A nonzero function on a null set has zero Lp seminorm.

[L1]

The previous counterexample supplies a measurable function h≢0 with hp=0 (A nonzero function on a null set has zero Lp seminorm).

[L2]

Lp(μ) is the representative function space before quotienting (The function space Lp(μ) for 0<p<).

Counterexample

Proof technique: Take the constant sequence equal to a nonzero function supported on a null set. Its distance to the zero function is 0, so it converges to both itself and 0 in the pseudometric on calligraphic Lp.

1.1

Let fn:=h for every n, where h is the function from [L1]. Then [L1, L2] (fn) is constant, hence Cauchy in the representative p-distance.

2.1

Also [L1, step 1.1] fnhp=0,fn0p=hp=0 for every n. So the same sequence converges both to h and to 0, even though those two functions are distinct pointwise.

3.1

Therefore the representative-space distance does not have unique limits [step 2.1] before passing to almost-everywhere classes. ∎

Depends on

Used by

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Dependency tree · two levels

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Sources