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A norm-closed nonconvex set need not be weakly closed
Statement refuted
Counterexample. Assume the Axiom of Choice (The Axiom of Choice). Let (Hilbert space, Square-summable families on an arbitrary index set and the space ) and let be its unit sphere. Then is norm closed and norm bounded, but it is not weakly sequentially closed: the coordinate vectors , the families that are at and elsewhere, lie in and satisfy . Indeed the weak closure of is the closed unit ball (Weak closure of the unit sphere is the closed unit ball). So the convexity hypothesis in A norm-closed convex set is weakly sequentially closed cannot be dropped, and a norm-closed admissible set need not be weakly closed for The direct method in a reflexive Banach space.
Facts & Assumptions
Given: The Axiom of Choice; the real Hilbert space (Hilbert space, Square-summable families on an arbitrary index set and the space ), its coordinate vectors , the families that are at and elsewhere, and its unit sphere . The counting-measure dictionary is the space of counting measure identifies with real , which is reflexive (and thus Banach) by Reflexivity of Lp for one less p less infinity under Countable Choice, supplied here by AC; the series pairing is its inner product.
The unit sphere of an infinite-dimensional Hilbert space is norm closed and norm bounded; its weak closure is the closed unit ball (Weak closure of the unit sphere is the closed unit ball).
Each coordinate vector satisfies , and : by the duality of and every bounded linear functional on is for a unique (Counting measure specializes the representation theorem to and ), so , and because a square-summable family has small tails, that is, for every there is a finite with (Square-summable families on an arbitrary index set and the space ), whence for every beyond all elements of ; weak convergence means convergence against every bounded linear functional (Weak convergence of nets and sequences). Hence the sequence lies in and converges weakly to the origin, which is not in .
A norm-closed convex set is weakly closed under the Axiom of Choice (A norm-closed convex set is weakly sequentially closed); the direct method's admissibility requirement is weak sequential closedness (The direct method in a reflexive Banach space).
Counterexample
is norm closed and norm bounded. The map is continuous for the norm topology and is closed in , so , its preimage, is norm closed; and for , so is norm bounded.
is not weakly sequentially closed. By [F2] the orthonormal sequence lies in , satisfies , and ; hence a sequence in converges weakly to a point outside , so is not weakly sequentially closed.
The failure is not an artefact of the sequence. By [F1] the full weak closure of is the closed unit ball, which strictly contains ; so is not weakly closed. This is a property of the set, independent of which witness sequence is used.
Conclusion. The set is norm closed (even bounded) but not weakly sequentially closed, so the convexity hypothesis in [F3] cannot be dropped; consequently a norm-closed nonconvex admissible set need not qualify for the direct method on the strength of norm closedness alone.
Depends on
- A norm-closed convex set is weakly sequentially closed
- The direct method in a reflexive Banach space
- Weak closure of the unit sphere is the closed unit ball
- Hilbert space
- Square-summable families on an arbitrary index set and the space $\ell^2(I)$
- Counting measure specializes the representation theorem to $\ell^p$ and $\ell^q$
- Weak convergence of nets and sequences
- The Axiom of Choice
- Reflexivity of Lp for one less p less infinity
- $\ell^p$ is the $L^p$ space of counting measure
Used by
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Sources
- Gerald Teschl, Partial Differential Equations: From Classical to Modern (2026 author manuscript; complete 392-page archived text) (standard reference, not scraped)
- Francesco Paolo Maiale (course by Giovanni Alberti), Lecture Notes Calculus of Variations A, University of Pisa (last update 21 August 2019; complete 149-page notes) (standard reference, not scraped)