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A norm-closed nonconvex set need not be weakly closed

Statement refuted

Counterexample. Assume the Axiom of Choice (The Axiom of Choice). Let H=ℓ2(N,R) (Hilbert space, Square-summable families on an arbitrary index set and the space ℓ2(I)) and let S={u∈H:∥u∥=1} be its unit sphere. Then S is norm closed and norm bounded, but it is not weakly sequentially closed: the coordinate vectors ej, the families that are 1 at j and 0 elsewhere, lie in S and satisfy ej⇀0∉S. Indeed the weak closure of S is the closed unit ball (Weak closure of the unit sphere is the closed unit ball). So the convexity hypothesis in A norm-closed convex set is weakly sequentially closed cannot be dropped, and a norm-closed admissible set need not be weakly closed for The direct method in a reflexive Banach space.

Facts & Assumptions

Given: The Axiom of Choice; the real Hilbert space H=ℓ2(N,R) (Hilbert space, Square-summable families on an arbitrary index set and the space ℓ2(I)), its coordinate vectors ej, the families that are 1 at j and 0 elsewhere, and its unit sphere S={u∈H:∥u∥=1}. The counting-measure dictionary ℓp is the Lp space of counting measure identifies H with real L2(#), which is reflexive (and thus Banach) by Reflexivity of Lp for one less p less infinity under Countable Choice, supplied here by AC; the series pairing is its inner product.

[F1]

The unit sphere of an infinite-dimensional Hilbert space is norm closed and norm bounded; its weak closure is the closed unit ball (Weak closure of the unit sphere is the closed unit ball).

[F2]

Each coordinate vector satisfies ej∈H, ∥ej∥=1 and ej⇀0: by the duality of ℓp and ℓq every bounded linear functional on ℓ2 is Λ(a)=∑jajbj for a unique b∈ℓ2 (Counting measure specializes the representation theorem to ℓp and ℓq), so Λ(ej)=bj, and bj→0 because a square-summable family has small tails, that is, for every ε>0 there is a finite F with ∑j∉F∣bj∣2<ε (Square-summable families on an arbitrary index set and the space ℓ2(I)), whence ∣bj∣2<ε for every j beyond all elements of F; weak convergence means convergence against every bounded linear functional (Weak convergence of nets and sequences). Hence the sequence (ej) lies in S and converges weakly to the origin, which is not in S.

[F3]

A norm-closed convex set is weakly closed under the Axiom of Choice (A norm-closed convex set is weakly sequentially closed); the direct method's admissibility requirement is weak sequential closedness (The direct method in a reflexive Banach space).

Counterexample

technique · direct verification with an orthonormal sequence
1.1F1algebra

S is norm closed and norm bounded. The map u↦∥u∥ is continuous for the norm topology and {1} is closed in R, so S, its preimage, is norm closed; and ∥u∥=1 for u∈S, so S is norm bounded.

1.2F2algebra

S is not weakly sequentially closed. By [F2] the orthonormal sequence (ej) lies in S, satisfies ej⇀0, and 0∉S; hence a sequence in S converges weakly to a point outside S, so S is not weakly sequentially closed.

1.3F1algebra

The failure is not an artefact of the sequence. By [F1] the full weak closure of S is the closed unit ball, which strictly contains S; so S is not weakly closed. This is a property of the set, independent of which witness sequence is used.

2.1F3step 1.2step 1.3∎

Conclusion. The set S is norm closed (even bounded) but not weakly sequentially closed, so the convexity hypothesis in [F3] cannot be dropped; consequently a norm-closed nonconvex admissible set need not qualify for the direct method on the strength of norm closedness alone.

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