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Not every abelian variety over a Dedekind function field extends to an abelian scheme

Statement refuted

Every abelian variety over the function field of a Dedekind scheme extends to an abelian scheme over that scheme, i.e. has good reduction.

Facts & Assumptions

Given: AC and DC, inherited from the cited suppliers; an algebraically closed field k of characteristic not 2 or 3, the complete discrete valuation ring R=k[ ⁣[t] ⁣] with fraction field K=k( ⁣(t) ⁣), and the smooth cubic Et:Y2Z=X3+tZ3 with origin O=[0:1:0], an elliptic curve over K.

[F1]

Multiplication by 2 on an abelian scheme of relative dimension one over a base where 2 is invertible is finite etale of rank 4, and over a complete DVR with separably closed residue field reduction of a finite etale scheme is a bijection on points (Multiplication by n on an abelian scheme is finite flat, and etale for n invertible, Finite etale schemes over a complete local ring and splitting).

[F2]

The two-torsion of Et is {O} together with the points with y=0, i.e. the roots of x3+t=0 in K (Two-torsion and uniqueness of the group law on a Weierstrass cubic, Valuative criterion for properness); good reduction means the existence of an abelian scheme model (Good reduction of an abelian variety over a Dedekind scheme).

Counterexample

technique · direct, by contradiction with the two-torsion count
1.1F2givenalgebra

The curve Et is an elliptic curve over K by the chord-tangent construction, and x3+t has no root in K=k( ⁣(t) ⁣): a root would satisfy 3v(x)=v(t)=1 for the valuation v, impossible for an integer valuation. Hence Et[2](K)={O} by [F2], a set with one element.

2.1F1F2step 1.1algebra

Suppose there were an abelian scheme model A→Spec⁡R with generic fibre Et. By [F1] multiplication by 2 is finite etale of rank 4 on A, so A[2] is finite etale over R; properness of A extends each K-point of A[2] uniquely to R, and finite etale lifting identifies A[2](R) with A[2](k). The special fibre is an elliptic curve over k (characteristic not 2), so A[2](k)=Z/2×Z/2 has four elements by the multiplication theorem, whence A[2](K)=Et[2](K) would have four elements, contradicting step 1.1.

3.1F1givenstep 2.1algebra∎

This contradiction proves that no abelian scheme model of Et over R exists: the elliptic curve Et has bad reduction. The companion example records the explicit ramified extension k( ⁣(s) ⁣) with s6=t over which the curve acquires good reduction, so the absence of a model over R is genuinely a failure of descent and not an artifact of the chosen equation.

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