Alphabeta Math
CounterexampleConstruction: Literature-sourcedVerification: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-09
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Analytic heat data need not give a time-analytic germ

Statement refuted

Analytic initial data alone do not guarantee time-analytic solvability of ut=uxx. For u(0,x)=1/(1+x2), any analytic solution at zero would have tku(0,0)=(1)k(2k)! for every k, and its time Taylor series would have radius zero.

Facts & Assumptions

Given: The heat equation ut=uxx and initial function g(x)=1/(1+x2). An analytic solution is assumed temporarily to derive the forced Taylor coefficients and a contradiction.

[F2]

The geometric series for ratio -x squared converges to the reciprocal when its modulus is below one. (For r<1, k0rk=1/(1r), and for r1 the series diverges).

[F3]

The principal symbol tests whether a normal covector is characteristic. (Characteristic covectors, hypersurfaces, and noncharacteristic data).

Counterexample

1.1

For x<1, the geometric identity gives 1/(1+x2)=k0(1)kx2k, hence the data are analytic with g(2k)(0)=(1)k(2k)!. If u were analytic, repeated differentiation of its equation and F1 would give tku=x2ku, beginning at k=0 and using tx2ku=x2kut=x2k+2u at each step. Evaluation on the initial trace gives the asserted derivatives.

givenF1algebraF2
2.1

The time coefficient is ak=(1)k(2k)!/k!. For every fixed t nonzero, ak+1tk+1/aktk=2(2k+1)t. Thus these terms eventually increase by a factor at least two and do not tend to zero. The time series diverges at every t nonzero and cannot represent an analytic germ. The PDE has total order two, with no u_tt term; its principal symbol is ξx2 and vanishes at dt. It therefore lies outside the noncharacteristic CK hypothesis.

step 1.1algebraF3

Source notes

Gantumur, §4 Example 21, printed p. 11; Ageno §2.4.1, PDF p. 28, specifies the data 1/(1+x²).

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Sources