Alphabeta Math
CounterexampleConstruction: Literature-sourcedVerification: AI-adaptedprecheck passaudited 2026-08-21
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
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y′=2∣y∣ has a continuum of delayed-start solutions through the origin

Statement refuted

Continuity of the right-hand side of a first-order IVP is enough for uniqueness. The continuous field f(y)=2∣y∣ refutes this: y′=2∣y∣ has distinct delayed-start solutions through the origin.

Facts & Assumptions

Given: For each c≥0, define yc(t)=0 for every t≤c and yc(t)=(t−c)2 for t≥c.

[L1]

For rational r>0, 0r=0 (Rational powers ar of a positive base).

[L2]

Local state-Lipschitz continuity requires one finite constant bounding the state difference quotient near the point (Local Lipschitz continuity in the state variable, locally uniform in time and parameters).

Counterexample

technique · direct
1.1givenL1algebra

On the first piece yc′=0=2∣yc∣ by [L1], on the second yc′=2(t−c)=2(t−c)2, and at t=c both one-sided derivatives are 0, so every yc is a solution through (0,0).

2.1step 1.1L2algebra∎

Distinct delays give distinct solutions, while ∣f(y)−f(0)∣/∣y∣=2/y for y>0, so [L2] rules out every finite local Lipschitz constant at zero.

Depends on

Used by

Dependency tree · two levels

24 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources