Alphabeta Math
CounterexampleConstruction: AI-adaptedVerification: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-13
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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Coordinate vectors do not converge weakly to zero in ell one

Statement refuted

The coordinate vectors of real or complex 1 converge weakly to zero. In fact they have no weak limit.

Facts & Assumptions

[F1]

The 1 norm is the sum of absolute values (p is the Lp space of counting measure), applied to real moduli in the complex case.

[F2]

Weak convergence requires convergence of every bounded scalar-linear functional (Weak convergence of nets and sequences).

Counterexample

Given: en with value one at coordinate n and zero elsewhere in 1.

1.1

Define F(x)=k=0xk. Absolute convergence gives a scalar sum, linearity by limits of finite sums, and F(x)kxk=x1. Thus F(1), but F(en)=1 for every n, whereas F(0)=0. Therefore en cannot converge weakly to zero.

givenF1F2
2.1

More generally coordinate evaluation Pk(x)=xk is bounded since xkx1. If enx, then xk=limnPk(en)=0 for each fixed k, so x=0, already excluded by step 1.1. Thus there is no weak limit.

step 1.1F1F2

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources