Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-13
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Coordinate vectors converge weakly to zero in ell p

Example

In real or complex p, 1<p<, the coordinate vectors en converge weakly to zero, although enp=1.

Facts & Assumptions

[F1]

Put q=p/(p1), so 1/p+1/q=1 (Conjugate exponents, including the endpoint conventions). The sequence norm is xp=(kxkp)1/p (p is the Lp space of counting measure); for complex sequences apply this to their real nonnegative moduli.

[F3]

Weak convergence tests every bounded scalar-linear functional (Weak convergence of nets and sequences).

Verification

Given: 1<p< and a bounded scalar-linear F on p.

1.1

Put bk=F(ek). For a finite initial segment let vk=bkbkq2 if bk0, and vk=0 if bk=0; set other coordinates zero. For real scalars conjugation fixes bk. Then bkvk=bkq and vkp=bk(q1)p=bkq. If AN=k<Nbkq, linearity and boundedness give AN=F(v)FAN1/p. If AN=0 there is nothing to divide; otherwise AN1/qF.

givenF1F2algebra
2.1

The nondecreasing partial sums AN are bounded by Fq, so their nonnegative series converges and bk0. Indeed infinitely many bkε>0 would make arbitrarily large finite sums exceed that bound. For completeness finite Hölder bounds k<Nxkbkxpbq, so the coefficient pairing is absolutely convergent, consistently over both fields. In particular F(en)=bn0 for every F, giving weak convergence. Directly enp=(1p)1/p=1, so there is no norm convergence to zero.

step 1.1F1F2F3

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

28 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources