Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-generatedprecheck passaudited 2026-08-02
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The exponent, product, quotient, and iterated-power laws for positive real bases and real exponents

Statement

For a,b>0 and r,s∈R, ar+s=aras,(ab)r=arbr,(a/b)r=ar/br,(ar)s=ars.

Facts & Assumptions

Given: Positive reals a,b and real exponents r,s.

[L2]

log⁡(ab)=log⁡a+log⁡b, log⁡(a/b)=log⁡a−log⁡b, and log⁡(exp⁡u)=u (Order, continuity, range, and the product, quotient, and reciprocal laws for the natural logarithm).

Proof

technique · direct
1.1

Expanding ar+s by [L1] and applying [L3] gives ar+s=exp⁡(rlog⁡a)exp⁡(slog⁡a)=aras.

L1L3
1.2

Expanding (ab)r and using log⁡(ab)=log⁡a+log⁡b gives (ab)r=arbr.

L1L2L3
1.3

The same calculation with log⁡(a/b)=log⁡a−log⁡b and [L3] gives (a/b)r=ar/br.

L1L2L3
2.1

Since log⁡(ar)=log⁡(exp⁡(rlog⁡a))=rlog⁡a, expanding (ar)s gives ars.

L1L2∎

Depends on

Used by

…and 8 more results.

Dependency tree · two levels

18 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources