Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-generatedprecheck passaudited 2026-08-02
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Change of base and inversion of the positive-base real exponential

Statement

If b>0, b≠1, and x>0, then log⁡bx=log⁡xlog⁡b,blog⁡bx=x,log⁡b(bu)=u(u∈R). In particular, log⁡bx=log⁡cx/log⁡cb for every second base c>0, c≠1.

Facts & Assumptions

Given: b,c>0 with b,c≠1, x>0, and u∈R.

[L1]

log⁡bx=log⁡x/log⁡b, with log⁡b≠0 (The logarithm to a positive base other than one).

[L3]

log⁡(exp⁡v)=v and exp⁡(log⁡x)=x for x>0 (Order, continuity, range, and the product, quotient, and reciprocal laws for the natural logarithm).

Proof

technique · direct
1.1

By [L1] and [L2], blog⁡bx=exp⁡((log⁡x/log⁡b)log⁡b)=exp⁡(log⁡x)=x.

L1L2L3
1.2

Likewise log⁡b(bu)=log⁡(exp⁡(ulog⁡b))/log⁡b=u.

L1L2L3
2.1

Dividing log⁡x first by log⁡c and then by log⁡b/log⁡c gives log⁡bx=log⁡cx/log⁡cb.

L1algebra∎

Depends on

Used by

Dependency tree · two levels

10 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources