Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-09
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Checking the subreciprocal condition for the loglog bound

Example

For ℓ(x)=log⁡2(1/x) on (0,1/2), the function is subreciprocal. At x=1/16 we have ℓ(x)=4 and log⁡2ℓ(x)=2, and the loglog density fraction with symbolic constant C>0 is 2−8C.

Facts & Assumptions

Given: ℓ(x)=log⁡2(1/x), 0<x<1/2, and C>0 symbolic.

[F1]

From Qid logarithmic and constant divisibility: Every nonempty finite graph H is ℓ-divisive for each of ℓ(x)=log⁡2(1/x) and ℓ(x)=2. Both functions are subreciprocal on (0,1/2).

[F2]

From Loglog quantitative induced density bound: δ=2−CH(log⁡2(1/x))2/log⁡2log⁡2(1/x).

Verification

1.1F1given

For 0<x<1/2, reciprocation and the increasing logarithm show ℓ(x)>1 and make ℓ nonincreasing. The bound log⁡2y≤y at y=1/x>2 implicit in the subreciprocity assertion [F1] gives ℓ(x)≤1/x. Thus all subreciprocal conditions hold, including positivity of log⁡2ℓ(x).

2.1F2step 1.1algebra∎

At x=1/16, 1/x=16=24, so ℓ(x)=4=22 and log⁡2ℓ(x)=2. Substituting in [F2] with CH=C gives exponent C⋅42/2=8C and fraction 2−8C. The parameter C remains symbolic.

Source notes

Proof/convention locator: Bucic, Nguyen, Scott and Seymour, Induced subgraph density I, 5.1 and 5.2.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

15 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources