Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-generatedprecheck passaudited 2026-08-02
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The exponential definition of real powers agrees with the existing rational powers

Statement

If a>0 and r∈Q, then the real power ar=exp⁡(rlog⁡a) agrees with the rational power of Rational powers ar of a positive base. For r>0, both conventions also give 0r=0.

Facts & Assumptions

Given: A positive real a and a rational r=p/q with q≥1.

[L1]

Rational powers satisfy (ap/q)q=ap, are positive for positive base, and obey the rational power laws (Rational powers ar of a positive base, Laws of rational exponents).

[L2]

For positive reals, log⁡(xy)=log⁡x+log⁡y, log⁡(1/x)=−log⁡x, and log⁡ is injective (Order, continuity, range, and the product, quotient, and reciprocal laws for the natural logarithm).

[L3]

The real-power definition is au=exp⁡(ulog⁡a) (Real powers for positive bases, with the zero-base positive-exponent convention).

Proof

technique · direct
1.1

For q≥1, the product law for log⁡ gives log⁡((ap/q)q)=qlog⁡(ap/q)=plog⁡a=log⁡(ap).

L1L2
2.1

Injectivity of log⁡ gives log⁡(ap/q)=(p/q)log⁡a, and exponentiating gives ap/q=exp⁡((p/q)log⁡a).

step 1.1L2L3
3.1

This is the new real power at exponent p/q; negative rational exponents follow by reciprocals, and the stated 0r convention agrees with Rational powers ar of a positive base for r>0.

step 2.1L1L3∎

Depends on

Used by

Dependency tree · two levels

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Sources