Alphabeta Math
CorollaryStatement: AI-adaptedProof: AI-generatedprecheck passaudited 2026-08-02
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Every rational approximation to a real exponent gives the same limiting real power

Statement

Let a>0, let x∈R, and let (qn) be a rational sequence converging to x. Then aqn→ax. Hence the limit is independent of the rational approximating sequence and equals the rational-supremum value a[x].

Facts & Assumptions

Given: a>0, x∈R, and rational qn→x.

[L1]

The rational-supremum and exponential constructions agree (The rational-supremum construction of real powers agrees with the exponential construction).

Proof

technique · direct
1.1

For every n, rational-exponent agreement gives aqn=exp⁡(qnlog⁡a).

L2
1.2

Continuity of t↦at gives aqn→ax.

L2
2.1

Since a[x]=ax, this limit is independent of the chosen rational sequence and has the asserted supremum value.

step 1.2L1∎

Depends on

Used by

Dependency tree · two levels

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Sources