Alphabeta Math
CorollaryStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passverified 2026-08-10 (gpt-5.6-terra-codex-subscription)
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The exponential is positive and satisfies exp(x)=1/exp(x)\exp(-x)=1/\exp(x)

Statement

For every real xx, exp(x)>0\exp(x)>0 and exp(x)=1exp(x).\exp(-x)=\frac1{\exp(x)}.

Facts & Assumptions

Given: xRx\in\mathbb R.

[L1]

exp(x+y)=exp(x)exp(y)\exp(x+y)=\exp(x)\exp(y) (The exponential addition formula exp(x+y)=exp(x)exp(y)\exp(x+y)=\exp(x)\exp(y)), and exp(0)=1\exp(0)=1 from The real exponential function and the number ee by a power series.

[L2]

Every nonzero square in an ordered field is positive (Squares of nonzero elements are positive).

Proof

technique · direct
1.1

Setting y=xy=-x in [L1] gives exp(x)exp(x)=1\exp(x)\exp(-x)=1, so both factors are nonzero.

L1algebra
2.1

Also exp(x)=exp(x/2)2\exp(x)=\exp(x/2)^2, so it is nonnegative; by step 1.1 and [L2] it is positive.

L1L2
3.1

Dividing the identity in step 1.1 by exp(x)\exp(x) gives the reciprocal formula.

step 1.1algebra

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 73 results over 15 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources