How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced — the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted — a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated — a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
Squares of nonzero elements are positive
Statement
Let be an ordered field (Ordered field) with positive cone . For every with we have , where . In particular, every nonzero square is positive.
Facts & Assumptions
Given: An ordered field with positive cone , and an element with .
, and by trichotomy for exactly one of , holds (Ordered field).
is closed under multiplication: if then (axiom O2 of Ordered field).
In any field, (Sign rules for products: and ).
Proof
Since , trichotomy leaves exactly two possibilities: or .
Case : then , so closure gives , i.e. .
Case : then , so closure gives ; since by L3, we get , i.e. .
The cases and exhaust all of by trichotomy, and both yield .
Depends on
Used by
- The exponential is positive and satisfies exp(-x)=1/exp(x) Corollary
- The multiplicative identity is positive Corollary
- The first quadrant of ℝ² contains 0 and is closed under addition and is not a linear subspace, since it is not closed under multiplication by -1 Counterexample
- x/(1+(k+1)²x²) converges uniformly to zero on ℝ while every derivative at zero equals one Counterexample
- The Euclidean inner product ⟨ x,y⟩ = ∑_k<n xₖ yₖ on ℝⁿ Definition
- √· on [0,∞) is uniformly continuous and exactly 1/2-Hölder, and is not Lipschitz Example
- Finite Jensen for x↦ x² gives that the square of a weighted mean is at most the weighted mean of the squares Example
- ℚ(√2) carries exactly two distinct field orders, exchanged by the conjugation √2 ↦ -√2 Example
- The Babylonian sequence x₁ = 2, xₖ₊₁ = (xₖ + 2/xₖ)/2 decreases to √2 Example
- The map x ↦ (x + 2/x)/2 is a contraction of [1,2] with fixed point √2, and the a priori bound gives the error after n steps Example
- The rational function field ℝ(t) ordered by the eventual sign is an ordered field, worked out Example
- FALSE: a^m/n := (a^1/n)ᵐ extends to negative bases False statement
- FALSE: every real number has a real square root False statement
- Bernoulli's inequality (1+x)ⁿ ≥ 1 + nx Lemma
- Every ordered field is an ordered ring, and its order is the one its positive cone induces Lemma
- For n ≥ 1 the product topology on n copies of the usual topology of ℝ is the metric topology of d_∞ on ℝⁿ, and hence also of d₁ and d₂, so ℝⁿ as a product and ℝⁿ as a metric space are one space Lemma
- Homomorphisms out of a complete ordered field are order-preserving Lemma
- ℝⁿ as the set of functions n → ℝ, and d₁, d₂, d_∞ are metrics on it Lemma
- Tangent is a continuous strictly increasing bijection from (-π/2,π/2) onto ℝ Lemma
- ℍ is a division ring that is not commutative, hence not a field: q⁻¹ = bar q / N(q) for q ≠ 0, while ij = k and ji = -k Theorem
- Square roots exist: a unique √a ≥ 0 with (√a)² = a; the positives are {x² : x ≠ 0} Theorem
- The arithmetic mean, geometric mean inequality Theorem
- The Cauchy-Schwarz inequality for finite sums Theorem
Dependency tree · next 3 levels
Direct dependencies and their dependencies through the next three levels: 4 results over 3 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.
Sources
- W. Rudin, Principles of Mathematical Analysis, 3rd ed., Ch. 1 (standard reference, not scraped)
- M. Spivak, Calculus, 4th ed., Ch. 1 (standard reference, not scraped)
- University of Innsbruck notes: Ordered fields (standard reference, not scraped)