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Dini's theorem fails for a discontinuous limit: powers on [0,1][0,1] decrease pointwise to a discontinuous endpoint indicator but not uniformly

Statement refuted

Refuted claim: continuity of the pointwise limit in Dini's theorem can be dropped.

On [0,1][0,1] let fk(x)=xk+1f_k(x)=x^{k+1}. These continuous functions decrease pointwise to the discontinuous endpoint indicator

χ(x)={0,0x<1,1,x=1,\chi(x)=\begin{cases}0,&0\le x<1,\\1,&x=1,\end{cases}

and the convergence is not uniform.

Facts & Assumptions

Given: The functions fk(x)=xk+1f_k(x)=x^{k+1} and the endpoint indicator χ\chi on [0,1][0,1].

[L1]

The powers xk+1x^{k+1} converge pointwise to χ\chi on [0,1][0,1] and do not converge uniformly there (fk(x)=xk+1f_k(x)=x^{k+1} converges pointwise but not uniformly on [0,1][0,1]).

[L3]

Dini's theorem on a closed interval requires the approximating functions and their pointwise limit to be continuous (Dini's theorem on a closed interval: monotone pointwise convergence of continuous functions to a continuous limit is uniform).

Counterexample

technique · direct
1.1

Each fkf_k is continuous by [L2].

L2
1.2

For x[0,1]x\in[0,1], fk+1(x)=xk+2=xxk+1xk+1=fk(x)f_{k+1}(x)=x^{k+2}=x\,x^{k+1}\le x^{k+1}=f_k(x), so the sequence is pointwise nonincreasing.

givenalgebra
1.3

The pointwise convergence to χ\chi and the failure of uniform convergence are [L1].

L1
1.4

The function χ\chi is discontinuous at 11: for every δ>0\delta>0, the point y:=1min{δ/2,1/2}y:=1-\min\{\delta/2,1/2\} lies in [0,1)[0,1) with y1<δ|y-1|<\delta and χ(y)χ(1)=1|\chi(y)-\chi(1)|=1.

L4algebra
2.1

Thus compactness, continuity of all approximants, and monotonicity hold, but the limit is discontinuous and the uniform conclusion fails; continuity of the limit in [L3] is indispensable.

step 1.1step 1.2step 1.3step 1.4L3

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