Alphabeta Math
CounterexampleConstruction: AI-adaptedVerification: AI-generatedprecheck passaudited 2026-08-02
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x2y/(x2+y2) has every directional derivative at the origin but is not totally differentiable there

Statement refuted

If every directional derivative of a real function exists at a point, then the function is totally differentiable there.

Facts & Assumptions

Given: f(0,0)=0 and f(x,y)=x2y/(x2+y2) away from the origin.

[L1]

The directional derivative is the derivative of t↦f(a+tv) at zero (Directional derivatives and partial derivatives of a map U⊆Rm→Rn).

[L2]

A total derivative computes every directional derivative, so v↦Dvf(a) would be the linear map Df(a) applied to v (A total derivative computes every directional derivative, and its matrix is the Jacobian).

Counterexample

technique · direct
1.1

For v=(a,b)≠0, f(ta,tb)=t a2b/(a2+b2), so [L1] gives Dvf(0,0)=a2b/(a2+b2); for v=0 it is 0.

L1L2
2.1

This direction map has value 0 at (1,0) and (0,1) but value 1/2 at their sum (1,1), so it is not additive.

step 1.1L2algebra
3.1

By [L2], total differentiability would make the directional-derivative map linear, contradicting step 2.1. Thus f is not totally differentiable at the origin.

step 1.1step 2.1∎

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

10 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources