Alphabeta Math
CounterexampleConstruction: Literature-sourcedVerification: AI-adaptedprecheck passverified 2026-08-10 (gpt-5.6-terra-codex-subscription)
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The exponential is not uniformly continuous on R

Statement refuted

The exponential function is uniformly continuous on R.

Facts & Assumptions

Counterexample

technique · direct
1.1L3

For n≥1, let xn=ι(n) and yn=ι(n)+1/ι(n). Then ∣yn−xn∣=1/ι(n)→0.

1.2L2given

By the mean value theorem, exp⁡(yn)−exp⁡(xn)=exp⁡(cn)/ι(n) for some cn∈(xn,yn). Since exponential is increasing, this is at least exp⁡(ι(n))/ι(n), which tends to +∞ by [L2].

2.1step 1.1step 1.2L1∎

Thus arbitrarily close pairs have image distances bounded away from 0, contradicting the uniform-continuity condition [L1].

Remarks

On every compact interval, exp⁡ is uniformly continuous by Heine-Cantor in R: a continuous real function on a compact subset of R is uniformly continuous; the failure is global.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

34 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources