Alphabeta Math
CounterexampleConstruction: Literature-sourcedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passverified 2026-08-10 (gpt-5.6-terra-codex-subscription)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced — the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted — a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated — a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The exponential is not uniformly continuous on R\mathbb{R}

Statement refuted

The exponential function is uniformly continuous on R\mathbb R.

Facts & Assumptions

Counterexample

technique · direct
1.1

For n1n\ge1, let xn=ι(n)x_n=\iota(n) and yn=ι(n)+1/ι(n)y_n=\iota(n)+1/\iota(n). Then ynxn=1/ι(n)0|y_n-x_n|=1/\iota(n)\to0.

L3
1.2

By the mean value theorem, exp(yn)exp(xn)=exp(cn)/ι(n)\exp(y_n)-\exp(x_n)=\exp(c_n)/\iota(n) for some cn(xn,yn)c_n\in(x_n,y_n). Since exponential is increasing, this is at least exp(ι(n))/ι(n)\exp(\iota(n))/\iota(n), which tends to ++\infty by [L2].

L2given
2.1

Thus arbitrarily close pairs have image distances bounded away from 00, contradicting the uniform-continuity condition [L1].

step 1.1step 1.2L1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 134 results over 21 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources