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Finite-dimensional Lie supermodule categories need not be semisimple
Statement refuted
Every finite-dimensional supermodule over every finite-dimensional complex Lie superalgebra is semisimple.
Facts & Assumptions
Given: The module , with even and odd.
Bracket data for gl(1|1): has the displayed four-dimensional graded basis and bracket table.
Two-dimensional highest-weight module data for gl(1|1): the action on is the specialization of the displayed family.
The two-dimensional gl(1|1) action is well-defined: this action satisfies the -supermodule identity.
Simple and semisimple Lie supermodules: semisimple means an internal direct sum of simple graded submodules.
The gl(1|1) bracket data define a Lie superalgebra: the bracket data define a complex Lie superalgebra.
Counterexample
Take and the finite-dimensional module from Two-dimensional highest-weight module data for gl(1|1) and The two-dimensional gl(1|1) action is well-defined. Its action is , , , , , , and . The line and the quotient are one-dimensional simple supermodules, but the extension does not split.
Proof technique: direct.
The subspace is a graded submodule: it is preserved by the diagonal operators , while . It is simple because it is one-dimensional and nonzero. The quotient line generated by is also simple: all act by zero on it.
The only graded complement to would have even part and zero odd part, since and . But , so this complement is not a submodule. Thus the exact sequence with submodule and quotient does not split.
Any nonzero graded submodule containing an even vector contains , hence also , and equals the whole module; a nonzero graded submodule with zero even part is exactly . Thus is the only simple graded submodule, and its direct sums cannot equal the -dimensional . By [F4], this module is not semisimple; [F5] confirms it is an instance covered by the refuted claim.
Depends on
Used by
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Sources
- Sigiswald Barbier, A minimal representation for the orthosymplectic Lie-superalgebra, §2.4 (standard reference, not scraped)