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The typicality boundary in a gl(1|1) highest-weight module

Example

For every (a,b)∈C2, let K(a,b) be the two-dimensional highest-weight supermodule from Two-dimensional highest-weight module data for gl(1|1), with highest vector v even and w=fv odd. It is simple exactly when the parameter is typical, namely when a+b≠0.

Facts & Assumptions

Given: The gl(1|1) module K(a,b)=Cv⊕Cw, its Z2-grading, and the highest-weight convention from the fixed triangular decomposition.

[F1]

The gl(1|1) bracket data define a Lie superalgebra: the positive subalgebra is Ce and the Cartan subalgebra is Ch1⊕Ch2.

[F2]

Highest-weight vectors and modules for a Lie superalgebra: a highest-weight vector is a nonzero homogeneous weight vector annihilated by the selected positive subalgebra.

[F3]

Two-dimensional highest-weight module data for gl(1|1): v has weight (a,b), ev=0, fv=w, and ew=(a+b)v.

[F4]

The two-dimensional gl(1|1) action is well-defined: these data make K(a,b) a supermodule and v a highest-weight vector.

[F5]

Typical and atypical highest weights for gl(1|1): this parameter is typical when a+b≠0 and atypical when a+b=0.

[F6]

Simple and semisimple Lie supermodules: a nonzero supermodule is simple when it has no proper nonzero graded submodule.

Verification

technique · direct
1.1F1F2F3F4F5F6given

By [F1], n+=Ce and h=Ch1⊕Ch2. The vector v is nonzero, even, has the displayed h-weight, and is killed by e, so [F2] and [F4] identify K(a,b) as the stated highest-weight supermodule. Its only nonzero proper graded subspaces are Cv and Cw, since its even and odd parts are one-dimensional. Neither is invariant when a+b≠0: fv=w∉Cv, while ew=(a+b)v∉Cw. By [F6], it is simple for a typical parameter.

2.1givenF3F4F5F6∎

If a+b=0, then ew=0, fw=0, and h1,h2 preserve Cw, so Cw is a nonzero proper graded submodule. By [F6], K(a,b) is not simple; by [F5], the parameter is atypical.

Depends on

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