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CounterexampleConstruction: Literature-sourcedVerification: AI-adaptedPipeline-generatedjudge pass (gpt-6-luna)verified 2026-10-22 (gpt-6.1-sol)
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The framed degree-one weight system does not pass through 1T

Statement refuted

Assume countable choice. The framed self-linking number of a framed oriented knot is the linking number of the knot with a sufficiently small push-off along its framing. Let D1 be the degree-one chord diagram consisting of an oriented circle with one chord. The framed self-linking invariant has a degree-one weight system w with w(D1)=2. Since D1 is isolated, the unframed 1T quotient sets it to zero. Therefore w does not factor through the unframed 4T+1T quotient. This counterexample distinguishes the framed and unframed diagram targets and makes no claim about separating knot types.

The diagram shows the isolated one-chord generator; the circle orientation fixes its cyclic skeleton and no proof relies on the picture.

D1

Facts & Assumptions

Given: Countable choice, the degree-one framed chord module, and its unframed quotient.

[A1]

The Axiom of Countable Choice (ACω): countable choice is the hypothesis used for the framed normal-bundle branch.

[F1]

Framed chord diagrams and four-term relations: the framed module imposes 4T; the unframed module additionally sets every isolated chord to zero.

[F2]

Vassiliev invariants induce weight systems: under countable choice, framed self-linking has type at most one and its degree-one derivative is a framed weight system taking value 2 on the one-chord diagram.

Counterexample

Given: As above.

1.1A1F1F2givenalgebra

The diagram D1 has one chord and no other chords, so that chord is isolated. In degree one there is no 4T generator, since 4T has two chords. Thus [F2] gives a valid framed weight system with w(D1)=2.

2.1F1F2step 1.1algebra∎

Every functional on the unframed quotient must vanish on D1, because [F1] imposes D1=0. If w factored through that quotient, it would satisfy w(D1)=0, contrary to w(D1)=2≠0 in Z. Hence the framed weight system does not descend through 1T.

Depends on

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