Alphabeta Math
CounterexampleConstruction: AI-adaptedVerification: AI-generatedprecheck passaudited 2026-08-01
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A left coset that is not the corresponding right coset in Sym⁡({1,2,3})

Statement refuted

For every subgroup H≤G and every g∈G, the corresponding cosets gH and Hg are equal.

Facts & Assumptions

Given: The group S3=Sym⁡({1,2,3}), the subgroup H={e,(12)}, and g=(123).

[F2]

The sets gH={gh:h∈H} and Hg={hg:h∈H} are the left and right cosets (Left and right cosets gH and Hg of a subgroup).

[F3]

Under rightmost-first composition, if τ=(12) then ee=e, eτ=τe=τ and τ2=e; hence e−1=e, τ−1=τ, and H={e,τ} contains the identity and is closed under products and inverses, so it is a subgroup (The symmetric group Sym⁡(X): the bijections of a set X under composition, Sym⁡(X) is a group under composition, and it is non-abelian whenever X has at least three distinct elements, Subgroup).

Counterexample

technique · direct
1.1

Direct composition gives (123)(12)=(13) and (12)(123)=(23).

F1
2.1

Therefore gH={(123),(13)} while Hg={(123),(23)}.

step 1.1F2F3
3.1

Since (13)≠(23), the left and right cosets are unequal, refuting the statement.

step 2.1∎

Depends on

Used by

Dependency tree · two levels

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Sources