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CounterexampleConstruction: AI-generatedVerification: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-06
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Omitting cross-block purity breaks the transversal conclusion

Statement refuted

It is false that one wide pure-partition block selected from each comb block must form a pure transversal if cross-block purity is omitted.

Facts & Assumptions

Given: Four comb blocks Bi={bi0,,bi7} and teeth ai. Each ai is complete to Bi and anticomplete to the other Bj. Take the one-block partitions A1i=Bi. Put precisely one edge, b10b20, between B1 and B2, and put no edges between any other distinct pair of blocks.

[F1]

The specified tooth/block incidences make these four pairs an (4,8)-comb (Combs in a graph).

[F2]

A pair is mixed when it is neither complete nor anticomplete (Edges between disjoint vertex sets; complete, anticomplete, pure and mixed pairs).

Counterexample

technique · direct finite adjacency check
1.1

Each one-block partition (A1i) is vacuously a pure blockade, and A1i=88/(24)=1; [F1] confirms that the ambient blocks are a comb.

F1givenalgebra
1.2

The pair (A11,A12) has the edge b10b20 but, for example, does not have b10b21. It is neither anticomplete nor complete, hence is mixed by [F2].

F2given
2.1

Therefore the four wide selected blocks are not a pure transversal. The missing cross-block-purity condition is exactly what fails here.

step 1.2F2

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources