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CounterexampleConstruction: AI-adaptedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-02
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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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xy/(x2+y2)xy/(x^2+y^2) has both partial derivatives at the origin but is discontinuous there

Statement refuted

If both partial derivatives of a real function exist at a point, then the function is continuous there.

Facts & Assumptions

Given: The function f(0,0)=0f(0,0)=0 and f(x,y)=xy/(x2+y2)f(x,y)=xy/(x^2+y^2) when (x,y)(0,0)(x,y)\ne(0,0).

[L1]

Partial derivatives are directional derivatives in the standard basis directions (Directional derivatives and partial derivatives of a map URmRnU\subseteq\mathbb{R}^m\to\mathbb{R}^n).

[L2]

A map is continuous at aa if its values tend to f(a)f(a) as the input tends to aa (Continuity of a map between metric spaces, at a point and globally, in the ε\varepsilon-δ\delta form).

Counterexample

technique · direct
1.1

Both axis restrictions of ff are identically zero, so [L1] gives xf(0,0)=yf(0,0)=0\partial_xf(0,0)=\partial_yf(0,0)=0.

L1L2
2.1

On the punctured diagonal (t,t)(t,t), f(t,t)=1/2f(t,t)=1/2.

step 1.1L2algebra
3.1

As (t,t)(0,0)(t,t)\to(0,0) but the values in step 2.1 do not tend to f(0,0)=0f(0,0)=0, [L2] shows that ff is discontinuous at the origin.

step 1.1step 2.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 108 results over 20 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources