Alphabeta Math
CounterexampleConstruction: AI-adaptedVerification: AI-generatedprecheck passaudited 2026-08-02
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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xy/(x2+y2) has both partial derivatives at the origin but is discontinuous there

Statement refuted

If both partial derivatives of a real function exist at a point, then the function is continuous there.

Facts & Assumptions

Given: The function f(0,0)=0 and f(x,y)=xy/(x2+y2) when (x,y)≠(0,0).

[L1]

Partial derivatives are directional derivatives in the standard basis directions (Directional derivatives and partial derivatives of a map U⊆Rm→Rn).

[L2]

A map is continuous at a if its values tend to f(a) as the input tends to a (Continuity of a map between metric spaces, at a point and globally, in the ε-δ form).

Counterexample

technique · direct
1.1

Both axis restrictions of f are identically zero, so [L1] gives ∂xf(0,0)=∂yf(0,0)=0.

L1L2
2.1

On the punctured diagonal (t,t), f(t,t)=1/2.

step 1.1L2algebra
3.1

As (t,t)→(0,0) but the values in step 2.1 do not tend to f(0,0)=0, [L2] shows that f is discontinuous at the origin.

step 1.1step 2.1∎

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

22 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources