Alphabeta Math
CounterexampleConstruction: AI-adaptedVerification: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-05
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The same middle group can support inequivalent extension maps

Statement refuted

Two extensions are equivalent whenever their middle groups are isomorphic.

Facts & Assumptions

Given: The middle group E=C9=Z/9Z, the quotient map

π(x)=x(mod3),

and the two kernel embeddings

i1(a)=3a,i2(a)=6a.

[L1]

The false statement above is the claim to be refuted (FALSE: equivalent extensions mean only that the middle groups are isomorphic).

Counterexample

technique · direct
1.1

The map π is surjective, with kernel {0,3,6}. Both i1 and i2 identify C3 with that kernel, so 1C3i1EπC31,1C3i2EπC31 are two extensions of C3 by C3 with the same middle group E.

givenalgebra
2.1

Any automorphism of E=C9 has the form ϕu(x)=ux with u(Z/9Z)×. If an extension equivalence existed, it would satisfy ϕi1=i2 and πϕ=π. The first identity gives 3u6(mod9), so u2(mod3). The second gives u1(mod3). This contradiction shows that no extension equivalence can exist.

step 1.1algebra
3.1

Thus the same middle group supports two inequivalent extension structures, refuting [L1].

L1step 2.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

3 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources