Alphabeta Math
CounterexampleConstruction: AI-adaptedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-02
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

sin(1/x) has no limit as x tends to zero

Statement refuted

The function xsin(1/x)x\mapsto\sin(1/x), defined for x0x\ne0, has a limit at 00.

Facts & Assumptions

Given: The punctured real line.

[L1]

sin(π/2+2mπ)=1\sin(\pi/2+2m\pi)=1 and sin(3π/2+2mπ)=1\sin(3\pi/2+2m\pi)=-1 for integers mm (Quarter-turn values and shifts by pi/2 and pi, The zero sets of sine and cosine and the least positive common period 2 pi).

Counterexample

technique · direct
1.1

For nNn\in\mathbb N, put xn=1/(π/2+2π(n+1))x_n=1/(\pi/2+2\pi(n+1)) and yn=1/(3π/2+2π(n+1))y_n=1/(3\pi/2+2\pi(n+1)). Both sequences are nonzero and tend to 00.

L3algebra
1.2

Their image values are sin(1/xn)=1\sin(1/x_n)=1 and sin(1/yn)=1\sin(1/y_n)=-1.

L1
2.1

A common function limit at zero would force both image sequences to converge to it, which is impossible.

step 1.1step 1.2L2

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 78 results over 19 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources