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The kernel row of a morphism of short exact sequences need not be short exact
Statement refuted
For every morphism of short exact sequences in an abelian category, the induced kernel row is itself short exact.
Diagram
diagram failed to render: 0 \arrow[r] & \mathbb Z \arrow[r, "\times 2"] \arrow[d, "\times 2"'] & \mathbb Z \arrow[r] \arrow[d, "\times 2"'] & \mathbb Z/2 \arrow[r] \arrow[d, "0"'] & 0 \\ 0 \arrow[r] & \mathbb Z \arrow[r, "\times 2"'] & \mathbb Z \arrow[r] & \mathbb Z/2 \arrow[r] & 0.
Facts & Assumptions
Given: In , the commutative diagram above.
The category is abelian (Abelian groups form an abelian category).
For such a diagram, the kernel row is exact at its first two nodes (The kernel row and cokernel row of a morphism of short exact sequences are exact at two nodes each).
Counterexample
Each row is short exact, and the vertical maps make a morphism of short exact sequences in the abelian category by [L1].
The kernels of the three vertical maps are So the kernel row is By [L2], it is exact at the first two nodes.
The last map in that row is the zero map , hence not epic. Therefore the kernel row is not short exact.
This refutes the statement.
Depends on
Used by
Dependency tree · two levels
12 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Saunders Mac Lane, Categories for the Working Mathematician, VIII.4 (standard reference, not scraped)