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Replacing the sphere measure by the ball measure in Kirchhoff's formula

Statement refuted

Statement refuted. "In the three-dimensional Kirchhoff formula one may replace the sphere measure dS on ∂Bct(x) by Lebesgue measure dy on the ball Bct(x) while keeping the sphere-area factor, i.e. u(x,t)=∂∂t[t(4πc2t2)−1∫Bct(x)u0]+t(4πc2t2)−1∫Bct(x)u1 still solves the Cauchy problem; the sphere area 4πc2t2 and the ball volume are interchangeable normalisations."

Facts & Assumptions

Given: Countable Choice, c>0, and the refuted expression displayed above.

[F1]

The Kirchhoff expression's solution for constant data (u0,u1)=(g0,v0) is g0+tv0; in particular (1,0) gives u≡1 and (0,1) gives u=t (Constant initial velocity in three dimensions, Kirchhoff's formula in three dimensions).

[F2]

∣Bct∣=43πc3t3 and ∣∂Bct∣=4πc2t2, since ∣Br3∣=ω2r3/3 and ∣∂Br3∣=ω2r2 with ω2=4π (Sphere and ball measures scale in Rn, The closed form for the volume of the unit n-ball, The real Gamma functional equation Γ(s+1)=sΓ(s), Γ(1/2)=π from the Gaussian integral).

Counterexample

1.1F1F2F3algebra

Constant displacement. Take u0≡1, u1≡0. The correct solution is u≡1 by [F1], whereas replacing the surface integral by a ball integral in the actual Kirchhoff expression gives ∂t[t(4πc2t2)−1(4πc3t3/3)]=∂t[ct2/3]=2ct/3. Its displacement limit is zero for every c>0, so it fails to attain u0=1. It also has velocity limit 2c/3, instead of zero.

1.2F1F2F3algebra

Constant velocity. Take u0≡0, u1≡1. The correct solution is u=t by [F1], whereas the refuted expression gives t(4πc2t2)−1(4πc3t3/3)=ct2/3. Its velocity limit is zero, not one, and its second time derivative is 2c/3 while its spatial Laplacian is zero. Thus it fails both the Cauchy data and the homogeneous wave equation for every c>0.

2.1F2step 1.1step 1.2algebra∎

The sphere-area normalisation converts a surface integral into the spherical mean. A ball integral divided by that same area instead returns ct/3 times the datum when it is constant. Keeping the factors t of Kirchhoff's formula then gives the two incorrect functions above. Hence sphere area and ball volume cannot be interchanged in that formula.

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