Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6.1-sol)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Kirchhoff's formula in three dimensions

Statement

Assume the Axiom of Countable Choice (The Axiom of Countable Choice (ACω)). Let c>0, u0∈C3(R3), u1∈C2(R3) and let M be the spherical mean of Spherical means and the weighted ball integral of space-dependent data. Then u(x,t):=∂∂t[t Mu0(x,ct)]+t Mu1(x,ct) defines a C2 function on R3×(0,∞) solving utt=c2Δu. Equivalently, for t>0, u(x,t)=14πc2t2∫∂Bct(x)(u0(y)+∇u0(y)⋅(y−x)+t u1(y)) dS(y), the sphere integral being the unnormalised form of the mean because ω2=4π (Sphere and ball measures scale in Rn). The formula uses the values of u0,u1 and the normal derivative of u0 on ∂Bct(x); pointwise agreement of the two data only on that sphere need not give the same solution value.

Facts & Assumptions

Given: Countable Choice, c>0, u0∈C3(R3), u1∈C2(R3), and the means A(x,r):=Mu0(x,r), B(x,r):=Mu1(x,r).

[F1]

For k≥1 and h∈Ck(R3), the spherical mean Mh is Ck on R3×(0,∞), every derivative being obtained by differentiating h under the sphere integral (Smoothness, parity and zero-radius limits of spherical means).

[F2]

For h∈C2(R3) one has ΔxMh(x,r)=Mrr(x,r)+2rMr(x,r) for r>0 (The Euler–Poisson–Darboux equation for spherical means).

[F3]

If f is totally differentiable at a and g at f(a), then g∘f is totally differentiable at a with D(g∘f)(a)=Dg(f(a))∘Df(a) (The chain rule for total derivatives: D(g∘f)(a)=Dg(f(a))∘Df(a)). The required total differentiability follows from continuous coordinate partial derivatives (If all partial derivatives exist on a neighbourhood and are continuous at a point, then the map is totally differentiable there with Jacobian derivative).

[F5]

If h is C2 on an open set of Rm, then ∂i∂jh=∂j∂ih (Clairaut--Schwarz theorem for continuous second partial derivatives).

[F6]

∣∂Br3∣=ω2r2 with ω2=3V3, and the map ω↦a+Rω multiplies surface measure by R2: ∫S2h(ω) dσ(ω)=R−2∫∂BR(a)h((y−a)/R) dS(y) (Sphere and ball measures scale in Rn, Agreement with the existing polar sphere measure).

Proof

1.1F1F3F4algebra

Time derivatives of the candidate. Write r=ct. By [F1] the means A,B are C3 respectively C2 on R3×(0,∞), so [F3] and [F4] give u=A+ctAr+tB, ∂tu=2cAr+c2tArr+B+ctBr and ∂t2u=3c2Arr+c3tArrr+2cBr+c2tBrr on R3×(0,∞), all derivatives being evaluated at (x,ct).

1.2F2F5F4algebra

Spatial derivatives. By [F2] applied to u0 and to u1, ΔxA=Arr+2rAr and ΔxB=Brr+2rBr; since A is C3 and ∂r commutes with the x-derivatives by [F5], ΔxAr=∂r(ΔxA)=Arrr+2rArr−2r2Ar. Hence Δu=ΔxA+ctΔxAr+tΔxB=(Arr+2rAr)+ct(Arrr+2rArr−2r2Ar)+t(Brr+2rBr) at (x,ct).

1.3F1F3F6F7algebra

The unnormalised form. Since ∣S2∣=ω2=4π by [F6] and [F7], Mu0(x,r)=14π∫S2u0(x+rω) dσ(ω)=14πr2∫∂Br(x)u0 dS, and likewise for u1; also ∂rMu0(x,r)=14π∫S2∇u0(x+rω)⋅ω dσ(ω)=14πr2∫∂Br(x)∇u0(y)⋅y−xr dS(y) by [F1], [F3] and the scaling in [F6]. Substituting r=ct into u=A+ctAr+tB and collecting the common factor 14πc2t2 gives u(x,t)=14πc2t2∫∂Bct(x)(u0(y)+∇u0(y)⋅(y−x)+tu1(y))dS(y).

2.1F4step 1.1step 1.2algebra

Comparison. Multiplying step 1.2 by c2 and substituting r=ct gives c2Δu=c2Arr+(2c/t)Ar+c3tArrr+2c2Arr−(2c/t)Ar+c2tBrr+2cBr=3c2Arr+c3tArrr+c2tBrr+2cBr. This equals utt from step 1.1, proving the equation. The C3 and C2 regularity of A and B gives u∈C2.

3.1step 2.1step 1.3∎

Both displays define the same C2 solution. The unnormalised display uses the data values and the normal derivative of u0 on the sphere, or equivalently the data on an open neighbourhood of that sphere.

Depends on

Used by

Dependency tree · two levels

75 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources