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The odd-dimensional wave formula by iterated spherical means

Statement

Assume the Axiom of Countable Choice (The Axiom of Countable Choice (ACω)). Let n=2k+1≥3 be odd, c>0, u0∈Ck+2(Rn), u1∈Ck+1(Rn), put Dt:=t−1∂t, and let M be the spherical mean of Spherical means and the weighted ball integral of space-dependent data. Then u(x,t):=1(n−2)!![∂∂tDtk−1(tn−2Mu0(x,ct))+Dtk−1(tn−2Mu1(x,ct))] defines a C2 function on Rn×(0,∞) solving utt=c2Δu; each Dtj is applied to the t-dependent function t↦tn−2Mf(x,ct). For n=3 (k=1) this is exactly Kirchhoff's formula Kirchhoff's formula in three dimensions, and the displayed constant (n−2)!! is the one required by the leading coefficient of Radial-derivative expansion of the Euler–Poisson–Darboux transform and its zero-radius limit.

Facts & Assumptions

Given: Countable Choice, n=2k+1≥3, c>0, u0∈Ck+2(Rn), u1∈Ck+1(Rn), and the spherical means Hf(x,r):=Mf(x,r).

[F1]

For j≥1 and every φ∈Cj+1((0,∞)), ∂r2Drj−1(r2j−1φ(r))=Drj−1[r2j−1r−2j∂r(r2j∂rφ(r))] on (0,∞), where Dr=r−1∂r (The iterated radial-derivative identity behind the odd-dimensional reduction).

[F2]

For m≥1 and h∈Cm(Rn), (x,r)↦Mh(x,r) is Cm on Rn×(0,∞) with all derivatives obtained by differentiating h under the sphere integral (Smoothness, parity and zero-radius limits of spherical means).

[F3]

For h∈C2(Rn) the Euler–Poisson–Darboux identity ΔxMh(x,r)=Mrr(x,r)+n−1rMr(x,r) holds for every r>0 (The Euler–Poisson–Darboux equation for spherical means).

[F4]
[F5]

If h is C2 on an open subset of Rm, then ∂i∂jh=∂j∂ih (Clairaut--Schwarz theorem for continuous second partial derivatives).

Proof

1.1F1F2

Fix f∈Ck+1(Rn) and put W(x,t):=Dtk−1(tn−2Hf(x,ct)), where n−2=2k−1. Applying [F1] with j=k and φ(t):=Hf(x,ct) — admissible for each fixed x because Hf(x,⋅)∈Ck+1 by [F2] — gives ∂t2Dtk−1(t2k−1Hf(x,ct))=Dtk−1[t2k−1t−2k∂t(t2k∂tHf(x,ct))].

1.2F3F4algebra

The inner expression. By [F4], ∂tHf(x,ct)=c (Hf)r(x,ct) and ∂t2Hf(x,ct)=c2(Hf)rr(x,ct), so with r=ct and 2k=n−1, t−1∂t(t2k∂tHf(x,ct))=t−1∂t(tn−1c(Hf)r(x,ct))=c tn−3[(n−1)(Hf)r(x,ct)+ct(Hf)rr(x,ct)]=c tn−3[(n−1)(Hf)r(x,r)+r(Hf)rr(x,r)]=c2tn−2ΔxHf(x,ct), the last equality because r((Hf)rr+n−1r(Hf)r)=rΔxHf by [F3].

1.3F5algebra

Hence ∂t2W(x,t)=c2Dtk−1(tn−2ΔxHf(x,ct)). The operator Δx acts only on the x-variables while Dtk−1 and multiplication by tn−2 act only on t, and the mixed partials involved commute by [F5] since Hf is Ck+1; therefore Dtk−1(tn−2ΔxHf(x,ct))=ΔxDtk−1(tn−2Hf(x,ct))=ΔxW(x,t), that is ∂t2W=c2ΔxW on Rn×(0,∞).

1.4F2algebra

Regularity and superposition. For f=u0∈Ck+2(Rn) the function t↦tn−2Hu0(x,ct) is Ck+2 by [F2], so Wu0=Dtk−1(⋅) is C3; for f=u1∈Ck+1(Rn) similarly Wu1 is C2. Hence u=(n−2)!!−1[∂tWu0+Wu1] is C2 on Rn×(0,∞) and utt=(n−2)!!−1[∂t∂t2Wu0+∂t2Wu1]=(n−2)!!−1[∂t(c2ΔxWu0)+c2ΔxWu1]=c2Δxu.

2.1given∎

For k=1, that is n=3, the formula reads ∂t[tMu0(x,ct)]+tMu1(x,ct) with (n−2)!!=1, which is Kirchhoff's expression of Kirchhoff's formula in three dimensions. The prefactor (n−2)!! is the leading coefficient of Drk−1(r2k−1φ) by Radial-derivative expansion of the Euler–Poisson–Darboux transform and its zero-radius limit: with r=ct and with the evenness of the means, which kills the first-order term, that expansion makes the normalised combination the data-carrying normalisation; the precise attainment of u0 and u1 is proved by the data-attainment lemma below.

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