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CorollaryStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-31
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A discrete embedded submanifold is locally closed and countable

Statement

Let S be a discrete embedded submanifold of a smooth manifold M. Then every point of S has a neighbourhood U in M such that SU is closed in U. Moreover S is countable.

Proof

technique · direct
1.1

Because S is discrete, its local dimension is 0. Thus by [F1], around each point pS there is a chart U in which SU corresponds to R0×{0}, that is, a single point. A singleton is closed in the chart domain, so SU is closed in U.

F1given
2.1

The manifold M is second countable, hence so is its subspace S by [L1]. Let B be a countable basis for S. Because S is discrete, every singleton {x} is open. Applying the basis property to the open set {x} shows that some BB satisfies xB{x}, hence B={x}. Thus every singleton of S is itself a member of the countable family B, so S is countable.

L1step 1.1
3.1

Therefore S is locally closed and countable.

step 1.1step 2.1

Depends on

Used by

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