Alphabeta Math
CorollaryStatement: Literature-sourcedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passjudge pass (gpt-5.6-terra)audited 2026-08-27
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A finite primitive group has at most two minimal normal subgroups

Statement

Let GSym(Ω) be finite and primitive. Then G has at most two minimal normal subgroups.

Facts & Assumptions

Given: A finite primitive permutation group GSym(Ω).

[L1]

Any two distinct minimal normal subgroups of G are regular (Two distinct minimal normal subgroups of a primitive group are regular).

[L2]

Distinct minimal normal subgroups centralize one another (Distinct minimal normal subgroups centralize one another).

[A1]

A regular permutation group has exactly one element sending a chosen point to a chosen point.

Proof

technique · direct
1.1

Suppose that M1,M2,M3 are three distinct minimal normal subgroups of G. By [L1], each pair among them is regular. In particular, M1 and M2 are both regular.

givenL1
2.1

Fix αΩ. Because M1 is regular, the map mmα identifies M1 with the set Ω, and because M2 is regular there is for each βΩ a unique element n(β)M2 with n(β)α=β by [A1].

A1step 1.1choose
3.1

Applying [L2] to the pair (M1,M3) shows that M3 centralizes M1. Hence every element of M3 acts on the identified copy of M1 by right translation. But M2 already has that property by step 2.1, and the right-regular subgroup centralizing the left-regular action of M1 is unique. Therefore M3=M2, contradicting distinctness. So no third minimal normal subgroup exists.

L2step 2.1algebra

Depends on

Used by

Dependency tree · two levels

8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources