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Ascoli–Arzelà in the uniform topology for nonempty compact metric domains

Statement

Assume the Axiom of Choice. Let X be a nonempty compact metric space, let Y be a metric space, and let F⊆C(X,Y). The closure of F in the uniform topology is compact if and only if F is metric-equicontinuous and pointwise relatively compact.

Facts & Assumptions

Given: Choice, a nonempty compact metric space X, a metric space Y, and F⊆C(X,Y).

[L1]

For a compact Hausdorff domain, compactness of the compact-open closure is equivalent to equicontinuity and pointwise relative compactness (Ascoli–Arzelà for a compact Hausdorff domain).

[L2]

On a nonempty compact metric domain, the published compact-open topology equals the uniform topology (On a nonempty compact metric domain, the compact-open topology is the uniform topology).

[L3]

Topological-domain and metric equicontinuity agree on a metric domain (Topological-domain equicontinuity agrees with metric equicontinuity on a metric domain).

[L4]

The general and published compact-open topologies agree on a metric domain (The general compact-open topology agrees with the published metric-domain definition).

Proof

technique · direct
1.1L1L5L6

By [L5] and [L6], X with its metric topology is compact Hausdorff, so [L1] applies to F.

1.2L2L4

By [L4] and [L2], the general compact-open topology used in [L1] is the uniform topology; hence the two closures and their compactness are identical.

2.1L1L3step 1.2∎

By [L3], the equicontinuity condition in [L1] is exactly metric equicontinuity. Pointwise relative compactness is unchanged, so [L1] becomes the claimed equivalence in both directions.

Depends on

Used by

Dependency tree · two levels

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Sources