Alphabeta Math
CorollaryStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-13
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Every bipartite graph with at least one edge has Turán density zero

Statement

If H is a finite bipartite graph with at least one edge, then

π(H)=0.

Facts & Assumptions

Given: The hypotheses and notation of the statement above.

[F1]

The complete bipartite graph KA,B has exactly all edges joining a vertex of A to a vertex of B (Empty and complete graphs, complete bipartite graphs, and the convention that Pn and Cn have n vertices).

[F2]

For s,t1, the Kővári–Sós–Turán theorem gives ex(N,Ks,t)=Os,t(N21/s) (Kővári–Sós–Turán: exact bipartite and ordinary-graph upper bounds for excluding Ks,t).

[F3]

For every finite graph H with an edge, the normalized extremal numbers converge to π(H), their infimum over n2 (Every finite graph with an edge has a Turán density π(H)=limnex(n,H)/(n2)).

Proof

technique · embed the forbidden graph in a complete bipartite graph
1.1

Choose a bipartition of H and enlarge its two sides, including any isolated vertices, to positive sizes s,t such that H is an ordinary subgraph of Ks,t. Every H-free graph is then Ks,t-free.

givenF1
2.1

Hence 0ex(n,H)ex(n,Ks,t)=Os,t(n21/s). Dividing by (n2) makes the right side tend to 0. The existing limit π(H) is therefore 0.

step 1.1givenF2F3
3.1

The at-least-one-edge hypothesis ensures both bipartition sides can be chosen positive and is exactly the scope in which the extremal density was defined.

step 1.1step 2.1

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 28 results over 9 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources