Alphabeta Math
CorollaryStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-13
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The asymptotic extremal density is determined exactly by chromatic number: π(H)=1−1/(χ(H)−1)

Statement

For every finite graph H with at least one edge,

π(H)=1−1χ(H)−1.

In particular, two such graphs have the same Turán density exactly when they have the same chromatic number, and every bipartite H has density 0.

Facts & Assumptions

Given: The hypotheses and notation of the statement above.

[F1]

If H is a finite graph with an edge and r=χ(H), then ex⁡(n,H)=(1−1/(r−1)+o(1))(n2) (Erdős–Stone–Simonovits: ex⁡(n,H)=(1−1/(χ(H)−1)+o(1))(n2) for every graph with an edge).

[F2]

For every finite graph H with an edge, the normalized extremal numbers converge to π(H), their infimum over n≥2 (Every finite graph with an edge has a Turán density π(H)=lim⁡n→∞ex⁡(n,H)/(n2)).

[F3]

Every finite bipartite graph with an edge has Turán density zero (Every bipartite graph with at least one edge has Turán density zero).

Proof

technique · identify the existing limit
1.1

Erdős–Stone–Simonovits states that the normalized extremal number tends to 1−1/(χ(H)−1), while the definition of π(H) is that same existing limit. This proves the formula.

givenF1F2
2.1

For integers r≥2, the function 1−1/(r−1) is strictly increasing, so equal values are equivalent to equal chromatic numbers. At r=2 it is 0, agreeing with the KST-derived bipartite corollary.

step 1.1givenF3
3.1

Steps 1.1-2.1 prove the exact density statement and both consequences.

step 1.1step 2.1∎

Depends on

Used by

Dependency tree · two levels

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Sources