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The Petersen graph has chromatic number 3, so its Turán density is 1/2

Example

Let P be the Petersen graph. Then

χ(P)=3andπ(P)=12.

Facts & Assumptions

Given: The hypotheses and notation of the statement above.

[F1]

In the Petersen graph's two-subset model, two vertices are adjacent exactly when the corresponding two-element subsets are disjoint (The Petersen graph on the two-element subsets of a five-element set, adjacent when disjoint).

[F2]

A proper k-vertex-colouring is a map c:Vk with c(u)c(v) for every edge {u,v}, its fibres are the colour classes, and χ(G)=min{kN:G is k-colourable} (Proper vertex colourings and chromatic number).

[F3]

For every finite graph H with an edge, π(H)=11/(χ(H)1) (The asymptotic extremal density is determined exactly by chromatic number: π(H)=11/(χ(H)1)).

Verification

technique · exhibit an odd cycle and a three-colouring
1.1

The vertices 12,34,15,23,45 form a 5-cycle in that order because consecutive pairs, including 45,12, are disjoint. Hence P is not bipartite and χ(P)3.

givenF1F2
1.2

Partition the ten vertices into {12,13,14,15}, {23,24,34}, and {25,35,45}. Within each class every two subsets intersect, so the Petersen adjacency definition gives no edge within a class. This is a proper three-colouring, hence χ(P)3.

givenF1F2
2.1

Steps 1.1-1.2 give χ(P)=3, and the density formula gives π(P)=11/(31)=1/2.

step 1.1step 1.2givenF3

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 46 results over 16 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources