Alphabeta Math
CorollaryStatement: AI-adaptedProof: AI-adaptedprecheck passaudited 2026-07-31
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Classical Möbius inversion over positive divisors

Statement

Let R be a commutative ring and let f,g:Z>0→R. Then

g(n)=∑d∣nf(d)for every n≥1

if and only if

f(n)=∑d∣nμ(n/d)g(d)=∑d∣nμ(d)g(n/d)for every n≥1.

All divisors in the sums are positive.

Facts & Assumptions

Given: A commutative ring R and functions f,g on the positive integers.

[L1]

Lower-finite poset inversion says g(n)=∑d∣nf(d) exactly when f(n)=∑d∣nμ∣(d,n)g(d) (Möbius inversion on a lower-finite poset, with the dual upper-finite form).

Proof

technique · direct
1.1

Apply [L1] to the lower-finite divisibility poset from [L3] and substitute [L2]. This gives f(n)=∑d∣nμ(n/d)g(d).

L1L2L3
2.1

The map d↦n/d is a bijection of the positive divisors of n with itself and is its own inverse. Reindexing the sum in step 1.1 by [L4] gives f(n)=∑d∣nμ(d)g(n/d).

step 1.1L4
3.1

Since [L1] is an equivalence, steps 1.1 and 2.1 prove both directions and both standard indexings.

step 1.1step 2.1L1∎

Depends on

Used by

Dependency tree · two levels

24 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources