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The Dirichlet series of the Möbius function is the reciprocal of the zeta Dirichlet series on Re s greater than 1
Statement
For ,
where .
Facts & Assumptions
Given: A complex number with .
The Möbius function satisfies that is, (Classical Möbius inversion over positive divisors, The Dirichlet-convolution identity and the constant-one function, The number-theoretic Möbius function from prime factorisation).
Products of absolutely convergent Dirichlet series multiply by Dirichlet convolution (Multiplying absolutely convergent Dirichlet series gives Dirichlet convolution).
For every rational , the series converges (For rational , converges iff ).
Proof
Write and choose a rational with . Since by [L1], one has By [L3], both Dirichlet series therefore converge absolutely.
By [L2],
Step 2.1 and the identity in [L1] make the right-hand side equal to , so the first factor is the reciprocal of .
Depends on
- The number-theoretic Möbius function $\mu(n)$ from prime factorisation
- Multiplying absolutely convergent Dirichlet series gives Dirichlet convolution
- Classical Möbius inversion over positive divisors
- The Dirichlet-convolution identity and the constant-one function
- For rational $p > 0$, $\sum 1/k^p$ converges iff $p > 1$
Used by
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Sources
- Kiran S. Kedlaya, Notes on Analytic Number Theory, Definition 2.8 (standard reference, not scraped)
- Jan-Hendrik Evertse, Analytic Number Theory, Chapter 2 (standard reference, not scraped)