Alphabeta Math
CorollaryStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

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Ramification indices account for the inertia quotient

Statement

Let G be finite, NG, and θIrr(N). List the distinct characters in Irr(Gθ) as χ1,,χr, and set ej=e(χj,θ). Then IndNGθ=j=1rejχj,j=1rej2=[IG(θ):N].

Facts & Assumptions

Given: The groups, modules, characters, and hypotheses in the statement. All representations here are finite-dimensional complex left representations.

[F1]

Finite-dimensional complex representations of a finite group are completely reducible. (If charkG, every finite-dimensional representation of G is completely reducible).

[F2]

Character induction and restriction satisfy Frobenius reciprocity for finite groups. (Frobenius reciprocity for complex characters).

[F3]

The multiplicity of an irreducible in a complex representation is the character inner product. (The multiplicity of an irreducible summand is a character inner product).

[F4]

For a character lying over θ, its ramification index is the multiplicity of θ in its normal restriction. (Clifford ramification index).

[F5]

The self-inner-product of IndNGθ equals [IG(θ):N]. (Normal subgroup induction criterion).

Proof

technique · direct
1.1

Decompose the nonzero induced module into simple G-modules by complete reducibility. The coefficient of an irreducible character ψ is IndNGθ,ψG=θ,ResNGψN. The latter is the nonnegative integer multiplicity of θ: conjugate symmetry of the inner product does not change that real integer. It is zero exactly outside the lying-over set and equals ej for ψ=χj. This proves the first identity and also that the finite list is nonempty.

F1F2F3F4given
2.1

Applying the multiplicity formula to each simple module itself gives χj,χkG=δjk. Taking the norm of the finite sum in step 1.1 therefore gives jej2. The normal-induction norm formula identifies this with [IG(θ):N]. If the index is one there is exactly one term with e=1; the formula also includes N=1 and N=G.

F3F5step 1.1algebra

Depends on

Used by

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Dependency tree · two levels

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Sources