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If , every finite-dimensional representation of is completely reducible
Statement
Let be a finite group, let be a field with , and let be a finite-dimensional representation of over . Then is completely reducible.
Facts & Assumptions
Given: A finite group , a field with , and a finite-dimensional representation of over .
A representation is completely reducible exactly when its underlying space is an internal direct sum of irreducible subrepresentations, and the zero representation is included by the empty direct sum (A completely reducible representation as a finite direct sum of irreducible subrepresentations).
A representation is irreducible when it is nonzero and has no proper nonzero subrepresentation (Subrepresentations, direct sums of representations, and irreducibility).
Under the characteristic hypothesis, every subrepresentation has a -invariant complement (Maschke's theorem for finite groups over fields whose characteristic does not divide ).
Every nonempty set of positive integers has a least element.
Proof
If , then [L1] makes completely reducible as the empty direct sum.
Assume now that , and as induction hypothesis suppose every representation of smaller dimension is completely reducible. Among the nonzero subrepresentations of , choose one with least positive dimension, using [A1]. It is irreducible by [L2], since any proper nonzero subrepresentation would have smaller positive dimension. Call this irreducible subrepresentation . By [L3], there is a subrepresentation with .
The subrepresentation is nonzero, so . The induction hypothesis therefore makes completely reducible. Using [L1] to expand that decomposition and adjoining the irreducible summand , one gets a direct-sum decomposition of into irreducible subrepresentations. Hence is completely reducible.
Depends on
Used by
- A cyclotomic field splits a finite group Corollary
- Every irreducible complex character occurs in the induction of an irreducible constituent of its restriction Corollary
- If char k ∤ |G|, then k[G] is a semisimple ring Corollary
- Over an algebraically closed field of characteristic 0, every element of finite order acts diagonalisably in a finite-dimensional representation Corollary
- Ramification indices account for the inertia quotient Corollary
- The complex Specht restriction branching rule Corollary
- The multiplicity of an irreducible summand is a character inner product Corollary
- Galois conjugates have equal scalar-extension multiplicity Lemma
- Isotypical evaluation and multiplicity subspaces Lemma
- Translation permutes normal isotypical components Lemma
- A faithful irreducible is induced from a proper inertia subgroup Proposition
- Absolute irreducibility via the endomorphism division algebra Theorem
- Finite-dimensional complex representations of a finite group are determined up to isomorphism by their characters Theorem
- Multiplicity-free complex Specht induction Theorem
- Scalar extension of an irreducible finite-group representation Theorem
- Schur index as minimal realization multiplicity Theorem
- Schur-Weyl decomposition and highest weights Theorem
- The normal subgroups of a finite group are exactly the intersections of kernels of irreducible complex characters Theorem
- Young's rule for complex permutation modules Theorem
Dependency tree · two levels
7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Peter Webb, A Course in Finite Group Representation Theory, Corollary 1.2.5 (standard reference, not scraped)
- Pavel Etingof et al., Introduction to Representation Theory, Theorem 3.1(i) (standard reference, not scraped)