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CorollaryStatement: Literature-sourcedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passjudge pass (z-ai/glm-5.2)audited 2026-07-31
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Assuming the ultrafilter lemma, a space is compact if and only if every universal net converges

Statement

Assume the ultrafilter lemma. A topological space is compact if and only if every universal net in it converges.

Facts & Assumptions

Given: A topological space XX and the ultrafilter lemma.

[L2]

Every net has a universal subnet (Assuming the ultrafilter lemma, every net has a universal subnet), and a cluster point of a universal net is a limit (Every cluster point of a universal net is a limit of that net).

[L3]

A point is a cluster point of a net exactly when some subnet converges to it (A point is a cluster point of a net if and only if some subnet converges to it).

Proof

technique · direct
1.1

If XX is compact, a universal net has a cluster point by [L1], hence converges by [L2].

L1L2
1.2

Conversely, suppose every universal net converges. Every net has a universal subnet by [L2], which then converges; its limit is a cluster point of the original net by [L3]. Thus every net has a cluster point.

L2L3
2.1

By [L1], this makes XX compact.

step 1.2L1

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 39 results over 8 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources