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TheoremStatement: AI-adaptedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passverified 2026-08-05 (claude-sonnet-5)
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Assuming the ultrafilter lemma, an arbitrary product of compact Hausdorff spaces is compact

Statement

Assume the ultrafilter lemma. If (Xi)iI(X_i)_{i\in I} is any family of compact Hausdorff spaces, then iIXi\prod_{i\in I}X_i, with its product topology, is compact.

Facts & Assumptions

Given: Compact Hausdorff spaces XiX_i, their product PP, and a universal net xdx_d in PP.

[L2]

Assuming the ultrafilter lemma, a space is compact if and only if every universal net in it converges (Assuming the ultrafilter lemma, a space is compact if and only if every universal net converges).

[L3]

Proof

technique · constructive
1.1

For every iIi\in I, the projection πi\pi_i is continuous, so πi(xd)\pi_i(x_d) is universal by [L1] and converges in compact XiX_i by [L2]. Its limit pip_i is unique by [L3].

L1L2L3
2.1

The uniqueness in step 1.1 defines a point piIXip\in\prod_{i\in I}X_i, namely the function ipii\mapsto p_i, rather than choosing a family of limits.

step 1.1L3construct
2.2

Let NN be a neighbourhood of pp in PP. By [L4], it contains a basic product neighbourhood restricting a finite set JIJ\subseteq I; for each iJi\in J, the coordinate net is eventually in its prescribed neighbourhood of pip_i. Directedness supplies one index after the finitely many thresholds, and after it xdNx_d\in N. Thus xdpx_d\to p.

step 1.1L4
3.1

Every universal net in PP converges by step 2.2. The converse direction of [L2] therefore makes PP compact.

step 2.2L2discharge-construct

Depends on

Used by

Dependency tree · next 3 levels

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