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Assuming the ultrafilter lemma, an arbitrary product of compact Hausdorff spaces is compact
Statement
Assume the ultrafilter lemma. If is any family of compact Hausdorff spaces, then , with its product topology, is compact.
Facts & Assumptions
Given: Compact Hausdorff spaces , their product , and a universal net in .
A continuous image of a universal net is universal (The image of a universal net under any map is universal, and a continuous map preserves its limits).
Assuming the ultrafilter lemma, a space is compact if and only if every universal net in it converges (Assuming the ultrafilter lemma, a space is compact if and only if every universal net converges).
In a Hausdorff space a net has at most one limit (A topological space is Hausdorff if and only if every net has at most one limit).
Basic product neighbourhoods restrict only finitely many coordinates (The product set of functions choosing a point in each factor, the projections, the box topology, and the product topology as the initial topology of the projections; the empty product is a one-point space).
Proof
For every , the projection is continuous, so is universal by [L1] and converges in compact by [L2]. Its limit is unique by [L3].
The uniqueness in step 1.1 defines a point , namely the function , rather than choosing a family of limits.
Let be a neighbourhood of in . By [L4], it contains a basic product neighbourhood restricting a finite set ; for each , the coordinate net is eventually in its prescribed neighbourhood of . Directedness supplies one index after the finitely many thresholds, and after it . Thus .
Every universal net in converges by step 2.2. The converse direction of [L2] therefore makes compact.
Depends on
- Every cluster point of a universal net is a limit of that net
- The image of a universal net under any map is universal, and a continuous map preserves its limits
- Assuming the ultrafilter lemma, a space is compact if and only if every universal net converges
- Assuming the ultrafilter lemma, compactness is equivalent to every net having a cluster point, every net having a convergent subnet, every filter having a cluster point, and every ultrafilter converging
- The product set $\prod_{i \in I} X_i$ of functions choosing a point in each factor, the projections, the box topology, and the product topology as the initial topology of the projections; the empty product is a one-point space
- A map into a product is continuous iff each of its components is; the projections are continuous and open; and each projection is surjective when every factor is nonempty, which for an infinite index set uses the Axiom of Choice
- Hausdorff space: distinct points have disjoint open neighbourhoods; every metrizable space is Hausdorff and the indiscrete topology on two points is not
- A topological space is Hausdorff if and only if every net has at most one limit
Used by
- Assuming the ultrafilter lemma, every Tychonoff space has a Hausdorff compactification Corollary
- Assuming the Ultrafilter Lemma and Countable Choice, an uncountable Cantor cube is compact Hausdorff and uniformizable but not first countable, hence not metrizable Example
- The coordinate-reading sequence in a compact binary cube has a convergent subnet but no convergent subsequence Example
- The compact Hausdorff product theorem uses the ultrafilter lemma, while the published arbitrary compact product theorem assumes the full Axiom of Choice Remark
Dependency tree · next 3 levels
Direct dependencies and their dependencies through the next three levels: 93 results over 13 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.
Sources
- WVU Math 581 Topology I (standard reference, not scraped)
- Tychonoff's theorem (Wikipedia) (standard reference, not scraped)
- Boolean prime ideal theorem (Wikipedia) (standard reference, not scraped)
- Net (mathematics) (Wikipedia) (standard reference, not scraped)