Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passjudge pass (z-ai/glm-5.2)audited 2026-07-31
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The image of a universal net under any map is universal, and a continuous map preserves its limits

Statement

If xx is a universal net in XX and f:XYf:X\to Y is any map, then f(x)f(x) is universal. If ff is continuous and xpx\to p, then f(x)f(p)f(x)\to f(p).

Facts & Assumptions

Given: A universal net x:DXx:D\to X and a map f:XYf:X\to Y.

[A1]

xx is universal precisely when it eventually enters every subset or its complement (Universal net: eventually in every subset or eventually in its complement).

Proof

technique · direct
1.1

Let SYS\subseteq Y. By [A1], xx is eventually in f1[S]f^{-1}[S] or in its complement f1[YS]f^{-1}[Y\setminus S]; respectively, f(x)f(x) is eventually in SS or in YSY\setminus S.

A1
2.1

Thus f(x)f(x) is universal.

step 1.1A1
3.1

If ff is continuous and xpx\to p, the second assertion is [L1].

L1

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 16 results over 8 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources