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Conditional expectation as a measurable function of the conditioning variable

Statement

Assume AC. Let X,Y take values in standard-Borel E,T, and let K be a disintegration kernel giving the conditional law of X given Y. For measurable f:E[0,], put h(y)=Ef(x)K(y,dx). Then h is measurable and E[f(X)σ(Y)]=h(Y)almost surely.

For measurable real f with Ef(X)<, define D={y:f(x)K(y,dx)<} and use the signed integral for h on D, zero off D. Then PY(D)=1, h is real measurable, and the same identity holds.

Facts & Assumptions

Given: The hypotheses and conventions in the statement.

[F1]

Under AC a disintegration kernel has the rectangle and all nonnegative joint-test identities. Disintegration of a joint law on standard borel spaces.

[F2]

A specified RCD integrates nonnegative or integrable tests to conditional-expectation versions. Conditional integration through a regular conditional law.

[F3]

Probability-kernel integration is measurable, including signed integration with zero filling. Measurability of integration against a kernel.

[F4]

AC covers disintegration existence and the inherited conditional-expectation class convention. The Axiom of Choice.

Proof

technique · direct
1.1

The product function (y,x)f(x) is measurable by the rectangle inverse-image test. Thus [F3] makes h measurable. The rectangle identities of [F1] make L(ω,A)=K(Y(ω),A) an RCD of X given σ(Y), since the events of that sigma-algebra are exactly inverse images of measurable Y-events. Applying [F2] to this L gives f(x)L(ω,dx)=E[f(X)σ(Y)] as classes, under [F4]. The integral on the left is h(Y) by its definition, which proves the nonnegative clause, allowing infinity.

F1F2F3F4
2.1

For real f, [F3] makes a(y)=f(x)K(y,dx) and D={a<} measurable and makes the zero-filled signed h real measurable. The nonnegative test identity of [F1] gives adPY=Ef(X)=C<. For every integer n1, nPY(Dc)C, hence PY(Dc)=0. Its inverse image under Y is null by the marginal definition. On that inverse-image complement the signed integral through L is h(Y), and on it both zero-fill conventions agree. The signed clause of [F2] therefore proves the stated real integrable conditional identity. Values at any fixed marginal-null fibre are not prescribed by this almost-sure identity.

step 1.1F1F2F3F4

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