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CorollaryStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-13
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Conservative fields are path-independent and have zero integral around every closed path

Statement

Let URn be open and let F:URn be conservative. Then F is path-independent. Moreover,

γFdr=0

for every closed piecewise-C1 path γ in U.

Facts & Assumptions

Given: The open set and conservative field in the Statement.

[L1]

Conservativity means that F=ϕ for some C1 potential ϕ, and path independence compares any two piecewise-C1 paths having the same endpoints (Piecewise-C1 path-connected domains, potential functions, conservative fields, and path independence).

[L2]

For every piecewise-C1 path γ, γϕdr=ϕ(γ(b))ϕ(γ(a)) (The gradient theorem: the line integral of a gradient is the endpoint increment).

Proof

technique · direct
1.1

Choose a potential ϕ as in [L1]. If α and β have the same initial point x and terminal point y, then [L2] gives αFdr=ϕ(y)ϕ(x)=βFdr.

givenL1L2
1.2

If γ is closed, then its two endpoint values agree, and [L2] gives γFdr=0.

givenL2algebra
2.1

Hence F is path-independent by [L1].

step 1.1L1
3.1

The closed-loop conclusion does not require connectedness: it is an endpoint calculation for each path that exists.

step 1.2

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 18 results over 7 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources