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CorollaryStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-16
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Under the Axiom of Countable Choice, countable products and Gδ subspaces of Polish spaces are Polish

Statement

Assume the Axiom of Countable Choice. A countable product of Polish spaces is Polish, and every Gδ subspace of a Polish space is Polish.

Facts & Assumptions

Given: The objects, hypotheses, and choice principles stated above.

[F1]

Assume the Axiom of Countable Choice. Every countable product of completely metrizable spaces is completely metrizable, including the empty product. (Under countable choice, a countable product of completely metrizable spaces is completely metrizable).

[F2]

Assuming ACω, a countable product of second countable spaces is second countable. (Assuming countable choice, a countable product of second countable spaces is second countable).

[F3]

Assume the Axiom of Countable Choice. A subspace of a Polish space is Polish if and only if it is a Gδ subset. (Under Dependent Choice, a subspace of a Polish space is Polish exactly when it is Gδ).

[F4]

Assume the Axiom of Countable Choice. For a completely metrizable space, separability is equivalent to second countability. Thus either countability convention gives the same notion of Polish space. (For completely metrizable spaces, the separable and second-countable definitions of Polish space agree under countable choice).

Proof

technique · direct
1.1

Use the product theorem for complete metrizability and the published theorem that countable products of second-countable spaces are second countable.

givenF2F1F4
2.1

For a Gδ subspace apply the Polish-subspace characterisation.

step 1.1F3F4
3.1

The preceding construction and implications establish the assertion.

step 2.1

Depends on

Used by

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Sources