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CorollaryStatement: Literature-sourcedProof: Literature-sourcedSession-authored (Fable 5 assisted)precheck passjudge pass (gpt-5.6-terra)audited 2026-08-27
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
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Dimension of a quotient via chains above an ideal

Statement

Let R be a commutative ring and let IR be an ideal. Assume R/I is nonzero. Then dim(R/I)=sup{n0:p0pn is a strict chain of prime ideals of R all containing I}. The supremum is allowed to be infinite.

Facts & Assumptions

Given: A commutative ring R, an ideal IR, and a nonzero quotient ring R/I.

[L1]

Krull dimension is the supremum of lengths of strict chains of prime ideals (Krull dimension of a nonzero ring).

[L2]

Prime ideals of R/I correspond exactly to prime ideals of R containing I, with strict inclusions preserved (Prime ideals of a quotient ring are exactly the prime ideals containing the ideal).

Proof

technique · direct
1.1

By [L2], strict chains of prime ideals in R/I are in bijection with strict chains of prime ideals of R whose every term contains I. Corresponding chains have the same length.

L2given
2.1

Since R/I is nonzero, [L1] applies to it. Thus dim(R/I) is the supremum of the lengths of the strict prime chains in R/I, and step 1.1 identifies that supremum with the one displayed in the statement.

L1step 1.1
3.1

Therefore dimension of the quotient is computed by prime chains of R lying above I.

step 2.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

5 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources